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Ainat [17]
4 years ago
9

Last year, Ivan had $30,000 to invest. He invested some of it in an account that paid 6% simple interest per year, and he invest

ed the rest in an account that paid 10% simple interest per year. After one year, he received a total of $2560 in interest. How much did he invest in each account?
First account : ?
Second account : ?
Mathematics
1 answer:
OlgaM077 [116]4 years ago
7 0
Hi there

0.06x+0.10 (30000-x)=2560
Solve for x
0.06x+3000-0.1x=2560
0.06x-0.1x=2560-3000
-0.04x=−440
X=440/0.04
X=11000 invested at 6%

30000-11000=19,000 invested at 10%

Hope it helps
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Given that a person was identified as a future terrorist, there is a 2.8544% probability that he/she actually is a future terrorist.

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A 99.9997% probability that a randomly chosen person is not a terrorist.

A 0.0003% probability that a randomly chosen person is a terrorist.

A 98% probability that a future terrorist is correctly identified

A 99.9% chance of correctly identifying someone who is not a future terrorist. This also means that there is a 0.01% probability of someone who is not a terrorist being identified as one.

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What is the probability of B happening, knowing that A has happened.

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P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

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What is the probability that the person is a terrorist, given that she was identified as a terrorist.

P(B) is the probability that the person is a terrorist. So P(B) = 0.000003

P(A/B) is the probability that the person was identified as a terrorist, given that she is a terrorist. The problem states that the system has a 98% chance of correctly identifying a future terrorist, so P(A/B) = 0.98

P(A) is the probability of a person being a identified as a terrorist. So

P(A) = P_{1} + P_{2}

P_{1} is the probability that a person is a terrorist and was identified as one. So:

P_{1} = 0.000003*0.98 = 0.00000294

P_{1} is the probability that a person is not a terrorist and, but was identified as one. So:

P_{2} = 0.999997*0.0001 = 0.0000999997

So

P(A) = P_{1} + P_{2} = 0.00000294 + 0.0000999997 = 0.000103

The answer is:

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.000003*0.98}{0.000103} = 0.028544

Given that a person was identified as a future terrorist, there is a 2.8544% probability that he/she actually is a future terrorist.

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