Answer:
50% of females do not satisfy that requirement
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

If a college includes a minimum score of 900 among its requirements, what percentage of females do not satisfy that requirement
This is scores lower than 900, which is the pvalue of Z when X = 900.
So



has a pvalue of 0.5
50% of females do not satisfy that requirement
Answer: 385
Given: error: 6 months, standard deviation = 5 years is 60 months
Step 1: find the minimal sample size ‘n’ for 95% confidence interval
1-0.95= 0.05
0.05/2= 0.025
Step 2:
1-0.025= 0.975
View attachment for more steps
Answer:
-24v + 8 by the distributive property
Step-by-step explanation:
Start by multiplying 6v by -4
-4 × 6v = -24
Then multiply -2 by -4
-2 × -4 = 8
When we add these together, we get the following:
-24v + 8
The scale factor from A to B is 5/3 and the value of r is 33/5
<h3>The scale factor from A to B</h3>
From the figure, we have the following corresponding sides
A : B = 5 : 3
Express as fraction
B/A = 3/5
This means that, the scale factor from A to B is 5/3
<h3>The value of r</h3>
From the figure, we have the following corresponding sides
A : B = 11 : r
Express as fraction
B/A = r/11
Recall that:
B/A = 3/5
So, we have:
3/5 = r/11
Multiply by 11
r = 33/5
Hence, the value of r is 33/5
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Answer:
d
Step-by-step explanation:
because it gets bigger so they are not going to have the same measures or lenghts.