Each page from 10 to 99, inclusive (so total of 90 pages) needs two digits (for example page 12 needs two digits: 1 and 2); Each page from 100 to 200, inclusive (so total of 101 pages) needs three digits (for example page 123 needs three digits: 1, 2 and 3)
Answer:

which agrees with answer C in your list of possible answers.
Step-by-step explanation:
We can use the general point-slope form of a line of slope m and going through the point
:

which in our case, given the info on the slope (2) and the point (-1, 4) becomes:

Answer:
a. 0.76
b. 0.23
c. 0.5
d. p(B/A) is the probability that given that a student has a visa card, they also have a master card
p(A/B) is the probability that given a student has a master card, they also have a visa card
e. 0.35
f. 0.31
Step-by-step explanation:
a. p(AUBUC)= P(A)+P(B)+P(C)-P(AnB)-P(AnC)-P(BnC)+P(AnBnC)
=0.6+0.4+0.2-0.3-0.11-0.1+0.07= 0.76
b. P(AnBnC')= P(AnB)-P(AnBnC)
=0.3-0.07= 0.23
c. P(B/A)= P(AnB)/P(A)
=0.3/O.6= 0.5
e. P((AnB)/C))= P((AnB)nC)/P(C)
=P(AnBnC)/P(C)
=0.07/0.2= 0.35
f. P((AUB)/C)= P((AUB)nC)/P(C)
=(P(AnC) U P(BnC))/P(C)
=(0.11+0.1)/0.2
=0.21/0.2 = 0.31
Answer:
5 = 1/4c
Step-by-step explanation:
Answer:
360 combinations
Step-by-step explanation:
To calculate the number of different combinations of 2 different flavors, 1 topping, and 1 cone, we are going to use the rule of multiplication as:
<u> 6 </u>* <u> 5 </u> * <u> 4 </u>* <u> 3 </u>= 360
1st flavor 2nd flavor topping cone
Because first, we have 6 possible options for the flavor, then we only have 5 possible options for the 2nd flavor. Then, we have 4 options for the topping and finally, we have 3 options for the cone.
It means that there are 360 different combinations of two different flavors, one topping, and one cone are possible