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grandymaker [24]
3 years ago
15

For questions 7 – 8, use the following functions: f(x) = 4x + 3x g(x) = 2x – 5 7. Find (f + g)(x). 8. Find (f – g)(x).

Mathematics
1 answer:
densk [106]3 years ago
8 0

Answer:

7) (f+g) (x) = 4^x + 5x -5

8) (f-g) (x) = 4^x + x - 5

Step-by-step explanation:

7)  Find (f +g)(x)

(4^x + 3x + 2x - 5)

(4^x + 5x -5)

(f+g) (x) = 4^x + 5x -5

8) Find (f-g)(x)

(4^x + 3x - 2x - 5)

(4^x + x - 5)

(f-g) (x) = 4^x + x - 5

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just olya [345]

Answer:

20.41

20=nearest whole number

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20.41=nearest hundredth

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Step-by-step explanation:

7 0
3 years ago
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Cereal is on sale this week. Is it a better buy to get the 10-ounce box for $1.76 or the 14-ounce box for $2.42?
Veseljchak [2.6K]

Answer:

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Step-by-step explanation:

4 0
2 years ago
Do you tailgate the car in front of you? About 35% of all drivers will tailgate before passing, thinking they can make the car i
Vesna [10]

Answer:

(a) The histogram is shown below.

(b) E (X) = 4.2

(c) SD (X) = 2.73

Step-by-step explanation:

Let <em>X</em> = <em>r</em><em> </em>= a driver will tailgate the car in front of him before passing.

The probability that a driver will tailgate the car in front of him before passing is, P (X) = <em>p</em> = 0.35.

The sample selected is of size <em>n</em> = 12.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 12 and <em>p</em> = 0.35.

The probability function of a binomial random variable is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x}

(a)

For <em>X</em> = 0 the probability is:

P(X=0)={12\choose 0}(0.35)^{0}(1-0.35)^{12-0}=0.006

For <em>X</em> = 1 the probability is:

P(X=1)={12\choose 1}(0.35)^{1}(1-0.35)^{12-1}=0.037

For <em>X</em> = 2 the probability is:

P(X=2)={12\choose 2}(0.35)^{2}(1-0.35)^{12-2}=0.109

Similarly the remaining probabilities will be computed.

The probability distribution table is shown below.

The histogram is also shown below.

(b)

The expected value of a Binomial distribution is:

E(X)=np

The expected number of vehicles out of 12 that will tailgate is:

E(X)=np=12\times0.35=4.2

Thus, the expected number of vehicles out of 12 that will tailgate is 4.2.

(c)

The standard deviation of a Binomial distribution is:

SD(X)=np(1-p)

The standard deviation of vehicles out of 12 that will tailgate is:

SD(X)=np(1-p)=12\times0.35\times(1-0.35)=2.73\\

Thus, the standard deviation of vehicles out of 12 that will tailgate is 2.73.

4 0
3 years ago
last year a school raised $19,950 by selling $15 tickets to a carnival fundraiser. this year the school will raise $20 per ticke
AURORKA [14]

Answer:

$26,600

Step-by-step explanation:

$19,950 / $15 = 1330 tickets

1330 x $20 = 26,600

7 0
3 years ago
26.68 is 58% of what number?
LekaFEV [45]
46 because 58% of 46 is equivalent to multiplying them I think so yeah 58% x 46 = 26.68
4 0
2 years ago
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