Step-by-step explanation:
We know that if (h,k) is the center of any circle and whose radius is = r then its equation is :
Given, the equation of circle
By comparing, we will get,
h = -2
k = 3
So, center of the circle is ( -2,3)
Does anyone know what lazor wulf is? if so send me a picture
1 answer:
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Table:
y = x²
can also be written as: f(x) = x²
Plug in each x value and calculate the output:
f(-4) = (-4)² = 16
f(-3) = (-3)² = 9
f(-2) = 4
f(-1) = 1
f(-) =
f(0) = 0
f() =
f(1) = 1
f(2) = 4
f(3) = 9
f(4) = 16
Answers:
a) graph shown in picture
b) vertex is at (0, 0)
