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bonufazy [111]
2 years ago
11

Answer both ASAP! please do correctly

Mathematics
1 answer:
Tresset [83]2 years ago
4 0

Answer:

1. the discriminant is 4

the number of solutions 0

solutions 0

2.the discriminant is 0

i couldn't find any solutions

Step-by-step explanation:

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HELPPPP PLEASE!!!! Don't understand
iragen [17]

Answer: 20% is your answer


Step-by-step explanation:

180-150=30

30 divided by 150 = .2 which is 20%

7 0
3 years ago
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Maths functions <br> please help!
Vlad [161]

Answer:

\textsf{1)} \quad f(x)=-x+3

2)   A = (3, 0)  and C = (-3, 0)

\textsf{3)} \quad g(x)=x^2-9

4)  AC = 6 units and OB = 9 units

Step-by-step explanation:

Given functions:

\begin{cases}f(x)=mx+c\\g(x)=ax^2+b \end{cases}

<h3><u>Part (1)</u></h3>

Given points:

  • H = (-1, 4)
  • T = (4, -1)

As points H and T lie on f(x), substitute the two points into the function to create two equations:

\textsf{Equation 1}: \quad f(-1)=m(-1)+c=4 \implies -m+c=4

\textsf{Equation 2}: \quad f(4)=m(4)+c=-1 \implies 4m+c=-1

Subtract the first equation from the second to eliminate c:

\begin{array}{r l} 4m+c & = -1\\- \quad -m+c & = \phantom{))}4\\\cline{1-2}5m \phantom{))))}}& = -5}\end{aligned}

Therefore m = -1.

Substitute the found value of m and one of the points into the function and solve for c:

\implies f(4)=-1(4)+c=-1

\implies c=-1-(-4)=3

Therefore the equation for function f(x) is:

f(x)=-x+3

<h3><u>Part (2)</u></h3>

Function f(x) crosses the x-axis at point A.  Therefore, f(x) = 0 at point A.

To find the x-value of point A, set f(x) to zero and solve for x:

\implies f(x)=0

\implies -x+3=0

\implies x=3

Therefore, A = (3, 0).

As g(x) = ax² + b, its axis of symmetry is x = 0.

A parabola's axis of symmetry is the midpoint of its x-intercepts.

Therefore, if A = (3, 0) then C = (-3, 0).

<h3><u>Part (3)</u></h3>

Points on function g(x):

  • A = (3, 0)
  • G = (1, -8)

Substitute the points into the given function g(x) to create two equations:

\textsf{Equation 1}: \quad g(3)=a(3)^2+b=0 \implies 9a+b=0

\textsf{Equation 2}: \quad g(1)=a(1)^2+b=-8 \implies a+b=-8

Subtract the second equation from the first to eliminate b:

\begin{array}{r l} 9a+b & =  \phantom{))}0\\- \quad a+b & =-8\\\cline{1-2}8a \phantom{))))}}& =  \phantom{))}8}\end{aligned}

Therefore a = 1.

Substitute the found value of a and one of the points into the function and solve for b:

\implies g(3)=1(3^2)+b=0

\implies 9+b=0\implies b=-9

Therefore the equation for function g(x) is:

g(x)=x^2-9

<h3><u>Part 4</u></h3>

The length AC is the difference between the x-values of points A and C.

\implies x_A-x_C=3-(-3)=6

Point B is the y-intercept of g(x), so when x = 0:

\implies g(0)=(0)^2-9=-9

Therefore, B = (0, -9).

The length OB is the difference between the y-values of the origin and point B.

\implies y_O-y_B=0-(-9)=9

Therefore, AC = 6 units and OB = 9 units

3 0
2 years ago
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Please help D: Given f (x) = 3 x minus 1 and g (x) = 2 x minus 3, for which value of x does g (x) = f (2)?
AfilCa [17]
<h3>Answer:   D.  x = 4</h3>

===============================================

Explanation:

First compute f(2)

f(x) = 3x-1

f(2) = 3(2) - 1 ... replace every x with 2; use PEMDAS to simplify

f(2) = 6 - 1

f(2) = 5

When we say g(x) = f(2), we really mean g(x) = 5

g(x) = 2x-3

2x-3 = g(x)

2x-3 = 5 .... plug in g(x) = 5

2x-3+3 = 5+3 ... add 3 to both sides

2x = 8

2x/2 = 8/2 ... dividing both sides by 2

x = 4

8 0
4 years ago
What do I do in the right side column
KIM [24]
The same thing to the other side
8 0
4 years ago
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NEED HELP ASAP
IrinaVladis [17]

Answer:

B sin 9° = cos 81°

As both values is

0.156434465

7 0
3 years ago
Read 2 more answers
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