In order to pass with a c in your class your going to need to get a 90% on your next test
Given:
The polynomials are:
To find:
The completely simplified sum of the polynomials.
Solution:
We have,
The sum of given polynomials is:
Therefore, the sum of the given polynomials is 
. It is a polynomial with degree 6 and leading coefficient -2.
Let r(cos O + i sin O) be a cube root of 125(cos 288 + i sin 288)
then
r^3(cos O + i sin O)^3 = 125(cos 288 + i sin 28)
so r^3 = 125 and cos 3O + i sin 3O = cos 288 + i sin 288
so r = 5 and 3O = 288 + 360p and O = 96 + 120p
so one cube root is 5 (cos 96 + i sin 96)
Im a little rusty at this stuff Its been a long time.
Im not sure of the other 2 roots
sorry cant help you any more
To find the total of 3/4 and 4/5 is to add them together. However, in order to add them together you need to find the least common denominator (LCD). And the LCD of both denominators would be 20, because that is the smallest number both 4 and 5 can divide into. And here is the tricky part, now you have to change the numerators. So since 3/4th's now has a denominator of 20 you have to make the 3 match the 20. So 4 times what it 20? It is 5. So now multiply 5 by three and that will give you 15/20, which can reduce to 3/4 which means that you did this correctly! Now repeat the same steps with 4/5:
4/5=4/20
20÷5=4
4•4=16
16/20 (16/20 can reduce to 4/5 which means you did this correctly.
Now to add them keep the denominators the same and only add the numerators:
15/20 + 16/20 = 31/20
Now this as a mixed number would be 1 11/20. I hope this was helpful!
