Answer:
1.5
Step-by-step explanation:
30/20
make y the subject
y= 5x + 3
perpendicular line needs the reciprocal of the gradient
y = 1/5x + c
substitute in the point
1 = 1/5(5) + c
5/5 = 1 so the answer is y = 1/5x
hope this is helpful!
<h3>Substitute and Check:</h3>
<h3>We can stop here and conclude that ( 1 , 3 ) is not a solution to this system, since it does not even satisfy the first equation, but check for the other one just in case:</h3>
D=vt
d=105 x 3
d=315
.....................
<span>1/(2x+3) = -x +7
cross-multiply
1 = (2x+3)(-x+7)
1 = -2x^2 +14x -3x +21
2x^2 -11x -20 = 0
use quadratic formula
x = {11 +/- sqrt(281)} /4
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or do you mean
1/2x + 3 = -x + 7
multiply all terms by x
1/2 + 3x = -x^2 + 7x
x^2 -4x = -1/2
x^2 -4x + 4 = 4 - 1/2
(x-2)^2 = 14/4
x-2 = +/-sqrt(14)/2
x = [4 +/- sqrt14] /2
hope this helps!</span>
