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ArbitrLikvidat [17]
3 years ago
15

PLEASE HELP ‼️50 POINTS‼️

Mathematics
1 answer:
nirvana33 [79]3 years ago
6 0

Answer: it is  4i78f4950

Step-by-step explanation:

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2m+4/8=w solve for m
Kisachek [45]

Answer: m=w/2-1/4

Step-by-step explanation: In the picture

8 0
3 years ago
Evaluate P(5, 2)<br><br> 20<br> 60<br> 240<br> 10
vesna_86 [32]

P(5,2) =  n! /(n-r)!

n = 5, r = 2:

= (5 x 4 x 3 x 2 x 1 ) /  3 x 2 x 1

Cancel out common factors:

= 5 x 4 = 20

The answer is 20.

3 0
3 years ago
Read 2 more answers
a pool is being filled with a large water hose. the height of the water in a pool is determined by 7g^2+3g-4. Previously the poo
ArbitrLikvidat [17]

If both the hoses are on the same time then the height of the water in the pool is given by the expression  15g^2 + 5g - 6

Step-by-step explanation:

(7g^2 + 3g - 4) + (8g^2 + 2g - 2)

= (7g^2 + 8g^2) + ( 3g + 2g) + (-4 -2)

with the help of distribution law,

= (7 +8)g^2 + (3 + 2)g - (4 + 2)

= 15g^2 + 5g - 6

Therefore if both the hoses are on the same time then the height of the water in the pool is given by the expression  15g^2 + 5g - 6

3 0
3 years ago
alan is spreading fertilizer on a field to get it ready for planting. The directions say to use 4/5 of a quart of fertilizer for
Ostrovityanka [42]

Answer:

48.6 quart of fertilizer

Step-by-step explanation:

The directions say to use 4/5 of a quart of fertilizer for each acre of land.

Alan has two fields,

Field 1

22 1/2 acre of land

1 acre of land = 4/5 quart

22 1/2 acre of land = x

Cross Multiply

x = 22 1/2 × 4/5

x = 45/2 × 4/5

x = 18 quart of fertilizer

Field 2

38 1/4 acres of land

1 acre of land = 4/5 quart

38 1/4 acre of land = x

Cross Multiply

x = 38 1/4 × 4/5

x = 153/4 × 4/5

x = 30.6 quart of fertilizer

The total fertilizer that Alan will need for his two fields is calculated as:

18 quart of fertilizer + 30.6 quart of fertilizer

= 48.6 quart of fertilizer

7 0
3 years ago
If a=bc, b=ca, c=ab find abc
Svetradugi [14.3K]
Fill in (2) in (1):

a=cca => c^2=1 => c=+1 or c=-1

Fill in (3) in (2)

b=aba => a^2=1 => a=+1 or a=-1

same for (1) in (2): b=+1 or b=-1

To satisfy all conditions at the same time, a, b and c all have to be +1 OR any two of them must be negative (e.g., a=b=-1, c=+1).

In all cases, abc=1
7 0
3 years ago
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