Answer: m=w/2-1/4
Step-by-step explanation: In the picture
P(5,2) = n! /(n-r)!
n = 5, r = 2:
= (5 x 4 x 3 x 2 x 1 ) / 3 x 2 x 1
Cancel out common factors:
= 5 x 4 = 20
The answer is 20.
If both the hoses are on the same time then the height of the water in the pool is given by the expression 15g^2 + 5g - 6
Step-by-step explanation:
(7g^2 + 3g - 4) + (8g^2 + 2g - 2)
= (7g^2 + 8g^2) + ( 3g + 2g) + (-4 -2)
with the help of distribution law,
= (7 +8)g^2 + (3 + 2)g - (4 + 2)
= 15g^2 + 5g - 6
Therefore if both the hoses are on the same time then the height of the water in the pool is given by the expression 15g^2 + 5g - 6
Answer:
48.6 quart of fertilizer
Step-by-step explanation:
The directions say to use 4/5 of a quart of fertilizer for each acre of land.
Alan has two fields,
Field 1
22 1/2 acre of land
1 acre of land = 4/5 quart
22 1/2 acre of land = x
Cross Multiply
x = 22 1/2 × 4/5
x = 45/2 × 4/5
x = 18 quart of fertilizer
Field 2
38 1/4 acres of land
1 acre of land = 4/5 quart
38 1/4 acre of land = x
Cross Multiply
x = 38 1/4 × 4/5
x = 153/4 × 4/5
x = 30.6 quart of fertilizer
The total fertilizer that Alan will need for his two fields is calculated as:
18 quart of fertilizer + 30.6 quart of fertilizer
= 48.6 quart of fertilizer
Fill in (2) in (1):
a=cca => c^2=1 => c=+1 or c=-1
Fill in (3) in (2)
b=aba => a^2=1 => a=+1 or a=-1
same for (1) in (2): b=+1 or b=-1
To satisfy all conditions at the same time, a, b and c all have to be +1 OR any two of them must be negative (e.g., a=b=-1, c=+1).
In all cases, abc=1
