Assuming the vertex of the triangle shown is the center of the pentagon, and the line segment shown is an altitude of the triangle:
If we join the center of (the circumscribed circle and of) the pentagon to the 5 vertices, 5 isosceles triangles are formed, all congruent to the one shown in the figure. It is clear that these triangles are congruent, so to find the area of the pentagon, we find the area of one of these triangles and multiply by 5.
The base of the triangle is 22.3 in, and the height is 15.4 ins, thus the area of the pentagon is:
5(Area triangle)=5*[(22.3*15.4)/2]=<span>858.55 (square inches).
Answer: </span>858.55 (square inches).
Answer:
Step-by-step explanation:
Area of the circle = 1400π
ie. πr^2 = 1400π . ie r^2 =1400. So r=10√14
Area A = πr^2.Differentiate w.r.t.t
dA/dt = 2πr. dr/dt
900 = 2×π×10√14 .dr/dt
So. dr/dt = 900/2×π×10√14 = 45/π√14 m/sec.
Hope this answer helps you :)
Have a great day
Mark brainliest
Answer:
Step-by-step explanation:
4/3-7/9=12/9-7/9=5/9.
Answer: 11/12
Step-by-step explanation: You need to make 4/6 by multiplying it by 2. 4/6 would become 8/12. You would then add it by 3/12 getting 11/12.
962-39=923 so your balance would be $846
923-56=867
867-138=729
729+117=846
