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Over [174]
3 years ago
13

The bank offers two kinds of checking accounts. Account A charges a fee of $.20 for each check that is written and has no monthl

y service charge. Account B charges $.10 for each check and has a monthly service charge of $1.50. How much would you save if you chose Account B and wrote 250 checks in a year?
Mathematics
1 answer:
Leya [2.2K]3 years ago
8 0
Account A.....with 250 checks
0.20(250) = 50

Account B...with 250 checks
0.10(250) + 1.50 = 25 + 1.50 = 26.50

so by using Account B, u r saving (50 - 26.50) = 23.50
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Help on precal, what are the answers?
Sloan [31]
1) cscΘ = - 2

=>

        1
      ------ = - 2
      sinΘ

=> sinΘ = - 0.5 => Θ is in the third and fourth quadrant

=> Θ = 180° + 30° = 210°

and Θ = 360° + 30° = 330°

2) tan Θ = √3

=> Θ = 60° and Θ = 180° + 60° = 240°
5 0
3 years ago
What is the expansion of (3+x)^4
Vlad1618 [11]

Answer:

\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81

Step-by-step explanation:

Considering the expression

\left(3+x\right)^4

Lets determine the expansion of the expression

\left(3+x\right)^4

\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i

a=3,\:\:b=x

=\sum _{i=0}^4\binom{4}{i}\cdot \:3^{\left(4-i\right)}x^i

Expanding summation

\binom{n}{i}=\frac{n!}{i!\left(n-i\right)!}

i=0\quad :\quad \frac{4!}{0!\left(4-0\right)!}3^4x^0

i=1\quad :\quad \frac{4!}{1!\left(4-1\right)!}3^3x^1

i=2\quad :\quad \frac{4!}{2!\left(4-2\right)!}3^2x^2

i=3\quad :\quad \frac{4!}{3!\left(4-3\right)!}3^1x^3

i=4\quad :\quad \frac{4!}{4!\left(4-4\right)!}3^0x^4

=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4

=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4

as

\frac{4!}{0!\left(4-0\right)!}\cdot \:\:3^4x^0:\:\:\:\:\:\:81

\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1:\quad 108x

\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2:\quad 54x^2

\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3:\quad 12x^3

\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4:\quad x^4

so equation becomes

=81+108x+54x^2+12x^3+x^4

=x^4+12x^3+54x^2+108x+81

Therefore,

  • \left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81
6 0
3 years ago
It takes Mike 60 minutes to vacuum a room, and Debbie 45 minutes.
elena55 [62]

Answer:

It takes Mike 15 more minutes to vacuum while it takes Debbie 15 more minutes to wash dishes

Step-by-step explanation:

Explain question properly pls.

3 0
2 years ago
106. Find the inverse g for each function f.<br> c.f(x) =23x+ 1
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I switched the x and y so it’s easier to see. The answer is (x-1)/(23).

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Solve fort:<br> 7<br> alg<br> 2NE<br> AS<br> Stuck? Watch a video<br> or hisobi<br> Gggggb zigzag
kozerog [31]
Wat does that mean
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