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3 years ago

15

If a pair of perpendicular lines are rotated, which is true?

1 answer:

aleksley [76]3 years ago

4 0

It is, " <span>Rotated parallel lines always remain parallel lines."

Hope this helps!
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I need a good joke :D

horrorfan [7]

Answer:

My life

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

Svetlanka [38]

Answer:

The line equation is y = 1.5x + 3

Fill the first space with '1.5' and the second with '3'

Step-by-step explanation:

The generic model for a line equation is:

y = ax + b

To find the parameters 'a' and 'b', we can use two points of the graph in the equation.

Using the point (0, 3), we have:

3 = 0*a + b

b = 3

Using the point (-2, 0) and the value of b above, we have:

0 = -2*a + b

2a = 3

a = 1.5

So the line equation is y = 1.5x + 3

3 0

3 years ago

8 to 11 do it with equations thx

Alenkasestr [34]

Answer:

Step-by-step explanation:

8. $4\geq x+\frac{3}{4}$

$4(4\geq x+\frac{3}{4} )$

$16\geq 4x + 3$

$-3$ $-3$

$13\geq 4x$

$\frac{13}{4}\geq \frac{4x}{4}$

$\frac{13}{4} \geq x = x\leq \frac{13}{4}$

$x\leq \frac{13}{4}=3.25$

9. $x-3\leq -8$

$+3$ $+3$

$x\leq -5}$

10. $4\leq x-7$

$+7$ $+7$

$11\leq x=x\geq 11$

11. 6.9 < x - 2.3

+ 2.3 + 2.3

9.2 < x = x > 9.2

Hope this helps!

5 0

2 years ago

For what value of x is sq 896z^15/225z^6 = xz^4/15

Ratling [72]

Answer:

Value of x is, 8

Step-by-step explanation:

Given: $\sqrt{\frac{896z^{15}}{225z^6}} =\frac{xz^4}{15} \sqrt{14z}$ ,.....[1]

To find the value of x:

Using exponent rules:

$(a^n)^m = a^{nm}$

$a^n \cdot a^m = a^{n+m}$

Taking square both sides in [1] we have;

$\frac{896z^{15}}{225z^6} = (\frac{xz^4}{15})^2 \cdot (14z)$

Simplify:

$\frac{896z^{15}}{225z^6} =\frac{x^2z^8}{225} \cdot (14z)$

or

$\frac{896z^{15}}{225z^6} =\frac{14x^2z^9}{225}$

Multiply both sides by $\frac{225}{14z^9}$ we get;

$x^2 = \frac{896 z^{15}}{225z^6} \times \frac{225}{14 z^9} = \frac{896 z^{15}}{14 z^{9+6}}$

Simplify:

$x^2 = \frac{896 z^{15}}{14 z^{15}} = 64$

or

$x = \sqrt{64}$

Simplify:

x = 8

Therefore, the value of x is, 8

5 0

3 years ago

PLEASE PLEASE ANSWER!

muminat

The area of the shaded region is $$8(\pi \ -\sqrt{3})\ \text{cm}^2$ .

Solution:

Given radius = 4 cm

Diameter = 2 × 4 = 8 cm

Let us first find the area of the semi-circle.

Area of the semi-circle = $\frac{1}{2}\times \pi r^2$

$$=\frac{1}{2}\times \pi\times 4^2$

$$=\frac{1}{2}\times \pi\times 16$

Area of the semi-circle = $$8\pi$ cm²

Angle in a semi-circle is always 90º.

∠C = 90°

So, ABC is a right angled triangle.

Using Pythagoras theorem, we can find base of the triangle.

$AC^2+BC^2=AB^2$

$AC^2+4^2=8^2$

$AC^2=64-16$

$AC^2=48$

$AC=4\sqrt{3}$ cm

Base of the triangle ABC = $4\sqrt{3}$ cm

Height of the triangle = 4 cm

Area of the triangle ABC = $\frac{1}{2}\times b \times h$

$$=\frac{1}{2}\times 4\sqrt{3} \times 4$

Area of the triangle ABC = $8\sqrt{3}$ cm²

Area of the shaded region

= Area of the semi-circle – Area of the triangle ABC

= $$8\pi \ \text{cm}^2-8\sqrt{3}\ \text{cm}^2$

= $$8(\pi \ -\sqrt{3})\ \text{cm}^2$

Hence the area of the shaded region is $$8(\pi \ -\sqrt{3})\ \text{cm}^2$ .

3 0

3 years ago