1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tatiyna
2 years ago
11

PLEASE PLEASE ANSWER!

Mathematics
1 answer:
muminat2 years ago
3 0

The area of the shaded region is $8(\pi \ -\sqrt{3})\ \text{cm}^2.

Solution:

Given radius = 4 cm

Diameter = 2 × 4 = 8 cm

Let us first find the area of the semi-circle.

Area of the semi-circle = \frac{1}{2}\times \pi r^2

                                      $=\frac{1}{2}\times \pi\times 4^2

                                      $=\frac{1}{2}\times \pi\times 16

Area of the semi-circle = $8\pi cm²

Angle in a semi-circle is always 90º.

∠C = 90°

So, ABC is a right angled triangle.

Using Pythagoras theorem, we can find base of the triangle.

AC^2+BC^2=AB^2

AC^2+4^2=8^2

AC^2=64-16

AC^2=48

AC=4\sqrt{3} cm

Base of the triangle ABC = 4\sqrt{3} cm

Height of the triangle = 4 cm

Area of the triangle ABC = \frac{1}{2}\times b \times h

                                          $=\frac{1}{2}\times 4\sqrt{3}  \times 4

Area of the triangle ABC =  8\sqrt{3} cm²

Area of the shaded region

                   = Area of the semi-circle – Area of the triangle ABC

                   = $8\pi \ \text{cm}^2-8\sqrt{3}\ \text{cm}^2

                   = $8(\pi \ -\sqrt{3})\ \text{cm}^2

Hence the area of the shaded region is $8(\pi \ -\sqrt{3})\ \text{cm}^2.

You might be interested in
In the right triangle shown, what is the value of x (to the nearest tenth)?
AVprozaik [17]
23.7 because you multiply
4 0
3 years ago
Read 2 more answers
My number has a tens digit that is right more than the ones digit. Zero is not one of my digits. What is the 2 digit number that
Helen [10]
If right is supposed to be eight then answer is 81
3 0
2 years ago
A rectangular prism that has a length of 8 feet, width of 6 feet, and height of 12 feet.
Alex

Answer:

576 cubic ft

Step-by-step explanation:

Volume of prism is = area of base of prism * height

given prism is rectangular with length of 8 feet and width of 6 ft

area of rectangle is = length * width

for the given prism area of base = 8 * 6 = 48 square ft

height of prism = 12ft

therefore volume of prism = area of base of prism * height

 = 48 square ft *12 ft = 576 cubic ft

 

6 0
3 years ago
Read 2 more answers
What is 0.000001 written as a power of ten?
AleksandrR [38]
a^{-n}=\dfrac{1}{a^n}\\\\10^{-n}=\dfrac{1}{10^n}=0.\underbrace{000...1}_{n}\\\\\text{examples:}\\\\10^{-2}=\dfrac{1}{10^2}=\dfrac{1}{100}=0.\underbrace{01}_{2} \\10^{-4}=\dfrac{1}{10^4}=\dfrac{1}{10,000}=0.\underbrace{0001}_{4}\\\\\text{therefore}\\\\0.\underbrace{000001}_{6}=10^{-6}\\\\\text{Answer:}\ \boxed{B.\ 10^{-6}}
7 0
3 years ago
What is 36.3 in % because i need help on test and teacher told me to get on this
saw5 [17]

3630 percent is your answer

6 0
3 years ago
Read 2 more answers
Other questions:
  • An isosceles triangle has an angle that measures 130°. Which other angles could be in that isosceles triangle? Choose all that a
    7·1 answer
  • Find the specified lengths and measures. Given: ΔABC≅ΔDEF Find: AB and m∠F
    7·1 answer
  • celia made 3 1/2 cups of rice. A serving of rice is 2/3 cups. how many servings of rice did celia make?
    9·1 answer
  • At one point the average price of regular unleaded gasoline was $3.57 per gallon. Assume that the standard deviation price per g
    14·1 answer
  • Which value, in order, will complete the table? ​
    9·1 answer
  • Write an equation in standard form passing through the points (-2,0) and (-3,-1).
    8·1 answer
  • In rhombus LMNO, the diagonals intersect at X. If mZLMO =<br> 32°, find mZMLO.<br> m.
    12·1 answer
  • HELPP PLS AND THANK YOU
    11·1 answer
  • Is this relation a function why or why not!?
    8·1 answer
  • Which property was used to simplify the expression?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!