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7nadin3 [17]
3 years ago
6

The systolic blood pressure of​ 18-year-old women is normally distributed with a mean of 120 mmHg and a standard deviation of 12

mmHg. What percentage of​ 18-year-old women have a systolic blood pressure that lies within 3 standard deviations of the​ mean?
(A) 68%
(B) 95%
(C) 100%
(D) 99.7%
Mathematics
1 answer:
seropon [69]3 years ago
3 0

Answer:

(D) 99.7%

Step-by-step explanation:

We are asked to find the percentage of​ 18-year-old women that will have a systolic blood pressure that lies within 3 standard deviations of the​ mean.

The empirical rule of normal distribution states approximately 68% of data lies within one standard deviation of mean, approximately 95% of data lies within two standard deviations of mean and approximately 99.7% of data lies within three standard deviations of mean.

Since the systolic blood pressure of​ 18-year-old women is normally distributed, therefore, 99.7% of 18-year-old women have a systolic blood pressure that lies within 3 standard deviations of the​ mean.

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In a survey, 24 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped
erica [24]

Answer:

The 98% confidence interval for the mean amount spent on their child's last birthday gift is between $40.98 and $43.02.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 24 - 1 = 23

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 23 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.98}{2} = 0.99. So we have T = 2.5

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.5\frac{2}{\sqrt{24}} = 1.02

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 42 - 1.02 = $40.98.

The upper end of the interval is the sample mean added to M. So it is 42 + 1.02 = $43.02.

The 98% confidence interval for the mean amount spent on their child's last birthday gift is between $40.98 and $43.02.

7 0
3 years ago
Please help ASAP!
Fudgin [204]

Amplitude:

we can see that

maximum value is 3

minimum value is -1

so,

A=\frac{max-min}{2}

A=\frac{3+1}{2}

A=2

Period:

It is time completed after which value repeats itself

so, we get

T=\pi -0

T=\pi

so,

option-D............Answer

5 0
3 years ago
At the ice cream shop, there are 14 shakes sold for every 6 malts. What is the ratio of malts to shakes?
lawyer [7]
6:14 simplified is 3:7. Hope it helps!
4 0
3 years ago
I need help on this question
Pavel [41]
I think the answer is D sorry if it’s wrong and good luck
7 0
3 years ago
What is 5(4+8c) Need Help
zysi [14]

Answer:

40c +20

Step-by-step explanation:

5(4+8c)

Expand

5\times 4 = 20\\5 \times 8c = 40c

= 20+40c\\\\=40c +20

6 0
3 years ago
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