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2 years ago

decide whether the following situation is looking for the part, the percent, or the whole: 81 of 271 pages in a book

Mathematics

1 answer:

lilavasa [31]2 years ago

6 0

Answer:

the whole

Step-by-step explanation:

i may be wrong

sorry

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What is the inverse of the function shown( in the form of a graph)

NemiM [27]

Answer:

$y = - 1x + b$

Step-by-step explanation:

The inverse of a slope is the exact opposite slope of the original. I'll show a function below where you can easily solve future problems if you need to.

$- \frac{1}{m} x$

m is the slope, so for the equation above, you simply insert the original slope, being 1, in the equation.

$- \frac{1}{1} x \\ - 1x$

So the inverse slope would be -1.

6 0

2 years ago

A submarine travels 6.6 km due West from its base and then turns and travels due South for 3.9

geniusboy [140]

Answer:

$7.7$ km

Step-by-step explanation:

The submarine's path from its base forms a right triangle when its final position is "connected" to the base. We know that the right triangle has legs of $6.6$ km and $3.9$ km, and we need to find the length of its hypotenuse. To do so, we can use the Pythagorean Theorem, which states that in a right triangle, $a^{2}+b^{2} =c^{2}$ , where $a$ and $b$ are the lengths of the triangle's legs and $c$ is the length of the triangle's hypotenuse. In this case, we know what $a$ and $b$ are, and we need to solve for c, so after substituting the given values of $a$ and $b$ into $a^{2}+b^{2} =c^{2}$ to solve for c, we get:

$a^{2}+b^{2} =c^{2}$

$6.6^{2} +3.9^{2} =c^{2}$ (Substitute $a=6.6$ and $b=3.9$ into the equation)

$43.56+15.21=c^{2}$ (Evaluate the squares on the LHS)

$58.77=c^{2}$ (Simplify the LHS)

$c^{2}=58.77$ (Symmetric Property of Equality)

$\sqrt{c^{2} } =\sqrt{58.77}$ (Take the square root of both sides of the equation)

$c=7.7,c=-7.7$ (Simplify)

$c=-7.7$ is an extraneous solution because you can't have negative distance, if that makes sense, so therefore, the submarine is approximately $7.7$ km away from its base. Hope this helps!