1. D= 500/40
2.D= 125/v
3.80= m/1.4
4.D= m/v
The median weight for shelter A is greater than that for shelter B.
The data for shelter B are a symmetric data set.
The interquartile range of shelter A is greater than the interquartile range of shelter B.
Hope this helps :-)
A = y(9 + 3x) factor y out of 9y+3yx, then devided both sides by (9+3x)
A/(9+3x) = y
Tan(30o)= ?/25
25 * tan(30o) = ?
? = 14.4