Answer: i know this is way late, but it’s 48
Step-by-step explanation:
Since point A is the separation of BE, both sides of the separation are equivalent, the are congruent. Since AB=24, you add 24+24 to get 48.
(I also just answered this question on homework and got it right, this is just how I did it.)
Answer: MP=(1,1)
Step-by-step explanation:

-2+4=2 -3+5=2
2/2=1
(-2,8) (1,2)
m=2-8/1-(-2)
m=-6/3
m= -2
y=-2x+b
(-2,8)
8=-2(-2)+b
8=-4+b
12=b
b=12
y=-2x+12
Hope this helps!
Answer:

A maximum of 112 number of 100 - kilograms can be loaded in the container.
Step-by-step explanation:
Given that:
Weight of each crate = 100 kg
The greatest weight that can be loaded in the container = 24000 kg
Weight already loaded in the container = 12800 kg
To find:
The inequality to determine the value
i.e. number of 100 - kilograms that can be loaded in the shipping container?
Solution:
Weight already loaded = 12800 kg
Let the number of 100 - kilograms that can be loaded in the container = 
Weight of
= 100
kg
This combined weight nor be greater than the capacity of the container.
OR we can say, it must be lesser than or equal to greatest weight that can be loaded into the container.


i.e. a maximum of <em>112</em> number of 100 - kilograms can be loaded in the container.
Answer:
Millions
Step-by-step explanation: