Answer:
Step-by-step explanation:
You would find your answer by dividing
<em>19.50/3.25 = 6 family members over 3 years old</em>
<em />
The solution for this problem is:
One way to solve is to using the "stars and bars"
approach, but this could be the other one:
x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 + x9 + x10 = 20
then use (20+10-1) C(10-1), this will
result to 29C9.
Then find the way to distribute x
as a result, (20-10+10-1) C (10-1) = 19C9
Thus, the probability is 19C9/29C9 or 0.0093
Answer:
-- State-A . . . Population = 1 · (1.08)ˣ
-- State-B . . . Population = 2 · (1.08)ˣ
' x ' = number of years after the original population
At the beginning, x=0.
Any quantity raised to the zero power = 1.
At the beginning, when x=0, the original populations were
State-A = 1 · 1 = 1
State-B = 2 · 1 = 2
The original population of State A was half of
the original population of State B.
this isn't my answer but hope it helps
Answer:
yes
Step-by-step explanation:
(there really isn't much else to say, it's quite simple)
The value is five hundred