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3 years ago

5

If Ben has 5 different color pairs of pants 8 different color shirts and 4 different color belts how many different combinations

are possible

1 answer:

EastWind [94]3 years ago

5 0

Answer:

4 because there are only 4 belts and he needs the belts

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Suppose you have 60 red marbles and 40 blue marbles in a

andrew-mc [135]

Answer: The required probability is 0.26.

Step-by-step explanation: Given that there are 60 red marbles and 40 blue marbles in a box 10 marbles are picked without replacement.

We are to find the probability of selecting 6 red marbles.

Since the marbles are picked up without replacement, so it is a situation of combination.

Let S denote the sample space of the experiment of drawing 10 marbles and E denote the event that 6 marbles are red.

So,

$n(S)=^{100}C_{10}=\dfrac{100!}{10!(100-10)!}=\dfrac{100!}{10!90!}=17310309456440,\\\\\\n(E)=^{60}C_6\times^{40}C_4=\dfrac{60!}{6!54!}\times\dfrac{40!}{4!36!}=50063860\times91390.$

Therefore, the probability of event E is given by

$P(E)=\dfrac{n(E)}{n(S)}=\dfrac{50063860\times91390}{17310309456440}=0.26.$

Thus, the required probability is 0.26.

6 0

2 years ago

This is due Monday but I want to get it done today, because the teacher is still going to check it, and I have practicly nothing

Crank

You don’t have anything attached:(

7 0

3 years ago

Enter the numerator that makes the equation true.

Gelneren [198K]

Answer:

1 3/4

Step-by-step explanation:

First write the equation in mixed fraction form as;

1 3/4 + 1 1/3 = 1 _/12 + 1 4/12 ⇒ 7/4 + 4/3 = _ + 16/12

7/4 + 4/3 = _ + 16/12

37/12 = _ + 16/12

37/12 - 16/12 = _

= 21/ 12

= 1 9/12

= 1 3/4

6 0

2 years ago

Suppose you have two urns with poker chips in them. Urn I contains two red chips and four white chips. Urn II contains three red

Neporo4naja [7]

Answer:

Multiple answers

Step-by-step explanation:

The original urns have:

Urn 1 = 2 red + 4 white = 6 chips
Urn 2 = 3 red + 1 white = 4 chips

We take one chip from the first urn, so we have:

The probability of take a red one is : $\frac{1}{3}$ (2 red from 6 chips(2/6=1/2))

For a white one is: $\frac{2}{3}$ (4 white from 6 chips(4/6=(2/3))

Then we put this chip into the second urn:

We have two possible cases:

First if the chip we got from the first urn was white. The urn 2 now has 3 red + 2 whites = 5 chips
Second if the chip we got from the first urn was red. The urn two now has 4 red + 1 white = 5 chips

If we select a chip from the urn two:

In the first case the probability of taking a white one is of: $\frac{2}{5}$ = 40% ( 2 whites of 5 chips)
In the second case the probability of taking a white one is of: $\frac{1}{5}$ = 20% ( 1 whites of 5 chips)

This problem is a dependent event because the final result depends of the first chip we got from the urn 1.

For the fist case we multiply :

$\frac{4}{6}$ x $\frac{2}{5}$ = $\frac{4}{15}$ = 26.66% ( $\frac{4}{6}$ the probability of taking a white chip from the urn 1, $\frac{2}{5}$ the probability of taking a white chip from urn two)

For the second case we multiply:

$\frac{1}{3}$ x $\frac{1}{5}$ = $\frac{1}{30}$ = .06% ( $\frac{1}{3}$ the probability of taking a red chip from the urn 1, $\frac{1}{5}$ the probability of taking a white chip from the urn two)

8 0

3 years ago

The perimeter of a basketball court is 84 meters and the length is 6 meters longer than twice the width. what are the length and

Colt1911 [192]

The length is 30 meters and the width is 12 meters.

3 0

3 years ago