Al2O3 is the formula 2 and 3 are subscripts
Answer:
That molecule is a propane.
Explanation:
Look at the scheme
H3C --------- ------ H
C
H3C --------- ------- H
C3H8
Answer : The partial pressure of is 102.3 mmHg.
Explanation :
As per question,
Mass of = 62.9 g
Mass of = 33.2 g
Molar mass of = 18 g/mole
Molar mass of = 62 g/mole
First we have to calculate the moles of and .
Now we have to calculate the mole fraction of and .
Now we have to partial pressure of .
According to the Raoult's law,
where,
= partial pressure of water vapor
= total pressure of gas
= mole fraction of water vapor
Therefore, the partial pressure of is 102.3 mmHg.
Answer:
15.9gmol⁻¹
The gas could have been methane when we compare the two molecular masses.
Oxygen gas, O₂ also shares this same number for its molecular mass. This would be the reason why it would not be methane.
Explanation:
Given parameters:
Volume of gas at STP = 2.0L or 2.0dm³(1L = dm³)
Mass of the gas = 1.43g
Unknown:
Molecular mass of the gas = ?
Solution
We can find the number of moles using the mole concept according to the equation below:
number of moles = ³⁻¹
number of moles =
number of moles = 0.089mol
Using this obtained number of moles, we can derive the molecular mass of the compound by using the relationship between mass and number of moles according to the equation below:
molecular mass =
molecular mass =
molecular mass of the gas = 15.9gmol⁻¹
The formula of methane gas is CH₄.
Let's calculate the molecular mass of methane using these atomic masses:
C = 12g and H = 1g
The molecular mass = 12 + (1x4) = 16gmol⁻¹
The gas could have been methane when we compare the two molecular masses.
Oxygen gas, O₂ also shares this same number for its molecular mass. This would be the reason why it would not be methane.
Answer: Combustion reactions are characterized by the reaction of a substance with O2 to form one or more oxygen, often water. Combustion reactions emit heat, and they are important because most of society's energy is derived from them. Ex.: CH4 (g) + 2O2 (g) -- CO2 (g) + 2H2O (g)
Explanation: I hope thus helps UwU