Answer:
1.059 x 10^24 formula units
Explanation:
103/58.44 = 1.76 moles NaCl
1.76 x 6.022 x 10^23 = 1.059 x 10^24
Answer:
Two elements in same group having similar properties.
Explanation:
The elements shows similar properties if they have same number of valance electrons.
As we move left to right in periodic table the number of valance electrons increases in case of every element
When we move top to down in the group of periodic table the number of valance electrons remain same. So the elements in same group shows similar properties.
For example:
Fluorine and chlorine are present in same group, both have same valance electrons so they shows similar properties.
Electronic configuration of fluorine.
F₉ = [He] 2s² 2p⁵
Electronic configuration of chlorine.
Cl₁₇ = [Ne] 3s² 3p⁵
Both have same number of valance electrons that's why showing similar physical and chemical properties.
Answer:
220
Explanation:
V₀= Vmax(D)/ (D) + km
0.66/100=vmax(130km)/(130km)+(km)
Vmax= 0.66×131/130×1000 =0.6650mm/d
kwat= vmax/ET
=0.665×10⁻³/ 3×10⁻⁶
= 0.22×10³
= 220
Answer:
Se requerirán 14.57 gramos de MgSO₄·7H₂O, que se disolverían en 105.43 gramos de agua.
Explanation:
Si tenemos 120 gramos de una solución al 10% de sulfato de magnesio en peso, habrán en la solución (120*10/100) 12 gramos de sulfato de magnesio (MgSO₄).
Sin embargo, el reactivo que está disponible es heptahidratado (MgSO₄·7H₂O), por lo que hay que calcular <em>cuántos gramos de sulfato de magnesio heptahidratado contendrán 12 gramos de MgSO₄</em>.
<u>Calculamos las moles de 12 gramos de MgSO₄</u>, usando su masa molecular:
- 12 g MgSO₄ ÷ 120.305 g/mol = 0.0997 mol MgSO₄.
<u>Después calculamos la masa de MgSO₄·7H₂O que contendrá 0.0997 mol MgSO₄</u>, usando la masa molecular de MgSO₄·7H₂O:
- 0.0997 mol * 246.305 g/mol = 14.57 g MgSO₄·7H₂O
Para saber la cantidad de agua en la que se disolverá el reactivo, restamos la masa de soluto de la masa total de la solución:
- 120 g - 14.57 g = 105.43 g
I would personally say a Controlled Variable because you are purposefully not spraying the other arm.