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Vaselesa [24]
2 years ago
15

Does the H₂SO4 solution contain ions? O yes O no

Chemistry
1 answer:
Artist 52 [7]2 years ago
8 0

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the concept of Ions .

If we see the reaction.

H2SO4 ==> 2H+ + (SO4)2-

Here you can see, H+ ( Hydrogen ions) and (SO4) 2- ( sulphate ions) are the ions when the H2SO4 is dissolved in water.

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Answer:

about 10 pounds

Explanation:

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6 0
3 years ago
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Discuss two physical and two chemical properties of Nitrogen​
Zigmanuir [339]

Answer:

Nitrogen gas (chemical symbol N) is generally inert, nonmetallic, colorless, odorless and tasteless. Its atomic number is 7, and it has an atomic weight of 14.0067. Nitrogen has a density of 1.251 grams/liter at 0 C and a specific gravity of 0.96737, making it slightly lighter than air.

Explanation:

7 0
3 years ago
List the number of each type of atom on the left side of the equation 2C10H22(l)+31O2(g)→20CO2(g)+22H2O(g)
Leokris [45]

<u>Answer:</u>

<em>20, 44, 62 </em>

<em></em>

<u>Explanation:</u>

To find the number of atoms of each element, we multiply coefficient and subscript  

For example 5 Ca_1 Cl_2 contains  

5 × 1 = 5 ,Ca atoms and

5 × 2 = 10, Cl atoms  

If there is a bracket in the chemical formula  

For example 3Ca_3 (P_1 O_4 )_2

we multiply coefficient × subscript × number outside the bracket to find the number of atoms  

(Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )

So

3 × 3 = 9 , Ca atoms  

3 × 1 × 2 = 6, P atoms  

3 × 4 × 2 = 24, O atoms are present.

So let us find the number of atoms of each element on the left  side of the equation  

2C_{10} H_{22} (l)+31O_2 (g)\Rightarrow 20CO_2 (g)+22H_2 O(g)

Number of C atoms = 2 × 10 = 20

Number of H atoms = 2 × 22 = 44

Number of O atoms = 31 × 2 = 62

20, 44, 62  are the Answers.

3 0
3 years ago
Mixtures can be separated into their components by taking advantage of differences in the chemical properties of the components.
Sedaia [141]
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4 0
3 years ago
A photon of light possesses 5 x 10^-19 J of energy. Calculate its frequency
saveliy_v [14]

Answer:

The frequency of photon is 0.75×10¹⁵ s⁻¹.

Explanation:

Given data:

Energy of photon = 5×10⁻¹⁹ J

Frequency of photon = ?

Solution:

Formula;

E = hf

h = planck's constant = 6.63×10⁻³⁴ Js

5×10⁻¹⁹ J =  6.63×10⁻³⁴ Js ×f

f =  5×10⁻¹⁹ J / 6.63×10⁻³⁴ Js

f = 0.75×10¹⁵ s⁻¹

The frequency of photon is 0.75×10¹⁵ s⁻¹.

4 0
3 years ago
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