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Vera_Pavlovna [14]
4 years ago
6

Will mark brainliest.

Mathematics
1 answer:
snow_tiger [21]4 years ago
3 0

The ordered pair (- 3, 1 ) is a solution to the second equation because it makes the second equation true

To test , substitute the coordinates of (- 3, 1) into the equations and if both sides are true then it is a solution to the equation.

x - 4y = - 3 - 4 = - 7 ≠ 6 ← not true

(3 × - 3) + 1 = - 9 + 1 = - 8 ← true

Thus (- 3, 1 ) is a solution to the second equation



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Answer:

(4,0) and (- 2,0): Answer

Step-by-step explanation:

Absolute value questions have two essential steps.

1. Solve the equation as it is written.

2. Solve it changing the sign of the right hand side. I will include a graph to confirm my answer

4*abs(x - 1) = 12             Divide by 4

  • abs(x - 1) = 12/4            
  • abs(x - 1) = 3                  Equate this to 3
  • x - 1 = 3                          Add 1 to both sides
  • x - 1 + 1 = 3 + 1               Combine
  • x = 4

4*abs(x - 1) = - 12         Divide by 4

  • abs(x - 1) = - 12/4
  • abs(x - 1) = - 3
  • x - 1 = - 3                       Add 1 to both sides
  • x - 1 + 1 = -3 + 1
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So this has 2 answers

(4,0) and (- 2,0)

5 0
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You can just 1) multiply the binomial by itself, or you can use 2) the square of a binomial pattern. I'll show it to you both ways.

1) Multiply the binomial by itself.

(3x - 2)^2 = (3x - 2)(3x - 2) =

Multiply every term of the first binomial by every term of the second binomial, then collect like terms. (This is often called using FOIL.)

= 9x^2 - 6x - 6x + 4

= 9x^2 - 12x + 4

2) Use the square of a binomial pattern

The square of a binomial is

(a - b)^2 = a^2 - 2ab - b^2

a^2 is the square of the first term.
b^2 is the square of the second term.
-2ab is the product of the two terms and 2.

You have

(3x - 2)^2,
where the first term is 3x, and the second term is -2

square the first term: 9x^2
square the last term: 4
the product of the terms and 2 is: -12x

Put it all together, and you get

9x^2 - 12x + 4

just like we got above with the other method.
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