Solve the inequality 5(2h+8)<60

CaHeK987 [17]

Answer:

The answer would be B: 8 ones, 4 tenths, and 5 hundredths.

Explanation:

First, you would have to use the equation: 1.57 + 6.88 = ?

Do the math, and 1.57 + 6.88 = 8.45

Now look at the answer choices. You can automatically get rid of every answer choice but B because none of them have an 8 in the ones place.

5 0

2 years ago

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Justin bought 5 apples and 4 oranges for £45. On another occasion, he bought 2 apples and 8 oranges which cost £50. Find the cos

Vitek1552 [10]

Answer:

the cost of 3 apples and 7 oranges be £15 and £35 respectively

Step-by-step explanation:

Let us assume the apple be x

And, the oranges be y

Now according to the question

5x + 4y = £45

And,

2x + 8y = £50

Multiply by 2 in equation 1

So,

10x + 8y = £90

2x + 8y = £50

8x = £40

x = £5

And, y be

5(£5) + 4y = £45

£25 + 4y = £45

4y = 20

y = £5

So, the cost of 3 apples and 7 oranges be £15 and £35 respectively

5 0

2 years ago

Quick is this right??? Answer and question in pic

Olin [163]

Answer:

-199

Step-by-step explanation:

put -6 in place of x in equation

3 0

3 years ago

To compare two programs for training industrial workers to perform a skilled job, 20 workers are included in an experiment. Of t

nikklg [1K]

Answer:

$t=\frac{19.1-23.3}{\sqrt{\frac{4.818^2}{10}+\frac{5.559^2}{10}}}}=-1.805$

$p_v =P(t_{(18)}$

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude the the true mean for method 1 is lower than the mean for the method 2 at 5% of significance

Step-by-step explanation:

Data given and notation

We can calculate the sample mean and deviation with these formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X_{1}=19.1$ represent the mean for the sample mean for 1

$\bar X_{2}=23.3$ represent the mean for the sample mean for 2

$s_{1}=4.818$ represent the sample standard deviation for the sample 1

$s_{2}=5.559$ represent the sample standard deviation for the sample 2

$n_{1}=10$ sample size selected 1

$n_{2}=10$ sample size selected 2

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the average time taken when training under method 1 is less than the average time for Method 2, the system of hypothesis would be:

Null hypothesis: $\mu_{1} \geq \mu_{2}$

Alternative hypothesis: $\mu_{1} < \mu_{2}$

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{19.1-23.3}{\sqrt{\frac{4.818^2}{10}+\frac{5.559^2}{10}}}}=-1.805$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n_{1}+n_{2}-2=10+10-2=18$

Since is a one sided test the p value would be:

$p_v =P(t_{(18)}$

Conclusion

If we compare the p value and the significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude the the true mean for method 1 is lower than the mean for the method 2 at 5% of significance

4 0

3 years ago

What is 30 divided into 896

a_sh-v [17]

Answer:

Math answers to fraction 896 divided by 30 can be calculated as follows.

896/30 math problems division = 29.8666666667. Therefore 29.8666666667 to 2 decimal places= 29.87

896/30 divided by 2 » (896/30) ÷ 2 » 29.8666666667 ÷ 2 = 14.9333333333 .

8 0

3 years ago

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