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Alex17521 [72]
3 years ago
15

Brian and Heidi went shopping at the mall. Brian spent 30% of the money he had on video games. Heidi spent 25% of her money on c

lothes. If Brian had $140 and Heidi had $180, who spent more money? Explain how you know.
Mathematics
2 answers:
andre [41]3 years ago
8 0
Heidi... if you use a proportion you can find this answer
Lunna [17]3 years ago
7 0
Brain :110

Heidi :155

Brian spent more he spent 30% and Heidi spent 25%

                         Brain
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Maybe try dividing 1092 by 21 I got 52
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In a fruit punch drink, the 3 ingredients are apple juice, orange juice and cranberry juice. If
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Answer:

its c

Step-by-step explanation:

its not that hard man you simply have to place the miles per seconds in an exponential graph

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Write a linear equation in point-slope form for the line that goes through (1, -3) and (3,9).
dimaraw [331]
The slope of the line is 6, meaning that you can eliminate A,C. Since the point slope formula is y-y1=m(x-x1) you just need to see if the points are correct.

B. (3,9)
D. (1,-3)

While these do contain one point, substitute the coordinates to see which contain both.

B.

(1,-3): -3-9=6(1-3): -12=-12
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D.

(1,-3): -3+3=6(1-1): 0=6(0); 0=0
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D is correct since the coordinate are on the line.

3 0
3 years ago
Read 2 more answers
Suppose that a company prints baseball cards. They claim that 30% of the cards feature rookies, 60% feature veterans, and 10% fe
liraira [26]

Answer:

H0: The distribution of players featured on the cards is 0.30 rookies, 0.60 veterans, and 0.10 All-Stars.

Ha: At least one of the proportions in the null hypothesis is false.

Step-by-step explanation:

On this case we need to apply a Chi squared goodness of fit test, and the correct system of hypothesis would be:

H0: The distribution of players featured on the cards is 0.30 rookies, 0.60 veterans, and 0.10 All-Stars.

Ha: At least one of the proportions in the null hypothesis is false.

And in order to test it we need to have observed and expected values. On this case we  can calculate the Expected values like this

E_{rookies}=50*0.3=15

E_{veterans}=50*0.6=30

E_{All stars}=50*0.1=5

The observed values are not provided. The statistic on this case is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i) -E_i}{E_i}

And this statistic follows a chi square distribution with k-1 degrees of freedom on this case k=3, since we have 3 groups.

We can calculate the p valu like this:

P(\chi^2 > \chi^2_{calculated})=p_v

And if the p value it's higher than the significance level we FAIL to reject the null hypothesis. In other case we reject the null hypothesis.

5 0
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