1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vinil7 [7]
3 years ago
6

Solve: 2 3 x - 4 = -2

Mathematics
2 answers:
andrew11 [14]3 years ago
6 0
Hi there!

23x - 4 = -2
23x = 2
x = 2/23

Hope this helps!
raketka [301]3 years ago
5 0
Is this 23x-4=-2??? I can't read what you have. if it is, the answer is 2/23
You might be interested in
Solve v = 1/3 bh for b the base of the cone
Viefleur [7K]

Answer:

<h2>b =  \frac{3v}{h}</h2>

Step-by-step explanation:

<h3>v =  \frac{1}{3} bh</h3>

First of all multiply through by 3

That's

<h3>3v =  \frac{1}{3}  \times bh</h3>

We have

<h3>3v = bh</h3>

Divide both sides by h to make b stand alone

That's

<h3>\frac{bh}{h}  =  \frac{3v}{h}</h3>

We have the final answer as

<h3>b =  \frac{3v}{h}</h3>

Hope this helps you

3 0
3 years ago
Evaluate √ 9.6230 * 2.340 / 5.3 10 * 3.721​
adoni [48]

Answer:

\sqrt{15.76}

Step-by-step explanation:

\sqrt{9.6230 \frac{2.340}{5.310}3.721 }

Lets solve the fraction first

\frac{2.340}{5.310} =0.44

9.6230 x 0.44 = 4.23

4.23 x 3.721 = 15.76

\sqrt{15.76}

7 0
3 years ago
Is 18,000g greater than 10kg?
oee [108]

Answer:

yes, 18,000g = 18kg

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
The probability that a lab specimen contains high levels of contamination is 0.10. Five samples are checked, and the samples are
raketka [301]

Answer:

(a) 0.59049 (b) 0.32805 (c) 0.40951

Step-by-step explanation:

Let's define

A_{i}: the lab specimen number i contains high levels of contamination for i = 1, 2, 3, 4, 5, so,

P(A_{i})=0.1 for i = 1, 2, 3, 4, 5

The complement for A_{i} is given by

A_{i}^{$c$}: the lab specimen number i does not contains high levels of contamination for i = 1, 2, 3, 4, 5, so

P(A_{i}^{$c$})=0.9 for i = 1, 2, 3, 4, 5

(a) The probability that none contain high levels of contamination is given by

P(A_{1}^{$c$}∩A_{2}^{$c$}∩A_{3}^{$c$}∩A_{4}^{$c$}∩A_{5}^{$c$})=(0.9)^{5}=0.59049 because we have independent events.

(b) The probability that exactly one contains high levels of contamination is given by

P(A_{1}∩A_{2}^{$c$}∩A_{3}^{$c$}∩A_{4}^{$c$}∩A_{5}^{$c$})+P(A_{1}^{$c$}∩A_{2}∩A_{3}^{$c$}∩A_{4}^{$c$}∩A_{5}^{$c$})+P(A_{1}^{$c$}∩A_{2}^{$c$}∩A_{3}∩A_{4}^{$c$}∩A_{5}^{$c$})+P(A_{1}^{$c$}∩A_{2}^{$c$}∩A_{3}^{$c$}∩A_{4}∩A_{5}^{$c$})+P(A_{1}^{$c$}∩A_{2}^{$c$}∩A_{3}^{$c$}∩A_{4}^{$c$}∩A_{5})=5×(0.1)×(0.9)^{4}=0.32805

because we have independent events.

(c) The probability that at least one contains high levels of contamination is

P(A_{1}∪A_{2}∪A_{3}∪A_{4}∪A_{5})=1-P(A_{1}^{$c$}∩A_{2}^{$c$}∩A_{3}^{$c$}∩A_{4}^{$c$}∩A_{5}^{$c$})=1-0.59049=0.40951

6 0
3 years ago
I need help! I would appreciate if you show me the work! Thank you !
iVinArrow [24]

Answer:

-11 for the first one and 0 for the second one

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Other questions:
  • What is the domain of the function?
    9·1 answer
  • How do solve an equation?
    5·1 answer
  • How many students must be randomly selected to estimate the mean weekly earnings of students at one college? we want 95% confide
    10·1 answer
  • The sum of one-third of a number and 5 is 27.<br> I need help plz!!
    15·2 answers
  • Explain how finding 7x20 is similar to similar to finding 7x2000.then find each product
    6·2 answers
  • SITUACIÓN 2: Confecciones
    10·1 answer
  • What is the product?<br> (-35 +21)(45-1)
    7·2 answers
  • 1 The Walters' backyard pool is rectangular in
    7·1 answer
  • Of<br> recipe. Which shows the correct amount of flour you need in the most reduced<br> form?<br> HE
    15·1 answer
  • What is the answer to the Pattern at 7 and counting by 7
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!