Complement of an angle = 90° - x.
Supplement of the complement of an angle = 180 - (90 - x).
= 180 - 90 + x
= 90 + x
Supplement of the complement of an angle less the complement of an angle = (90 + x) - (90 - x)
= 90 + x - 90 + x
= 2x
Now, the quotient of the supplement of the angle and the number 3 is
.
It is given that supplement of the complement of an angle less the complement of an angle exceeds the quotient of the supplement of the angle and the number 3 by 73.
Therefore, 2x = 

Multiply both sides by 3.
6x = 180 - x + 219
= 399 - x
Add x to both sides.
6x + x = 399
7x = 399
Divide both sides by 7.
x = 57
Hence, the required angle = 57°.
I don’t get it please explain more
Answer:
0.88m²
Step-by-step explanation:
Area of a trapezium = 1/2(a+b)h
a and b are the parallel sides
h is the height
Given
a = 1m
b = 1.2m
h = 0.8m
Substitute
Area of the trapezium = 1/2(1+1.2)(0.8)
Area of the trapezium = 1/2(2.2)(0.8)
Area of the trapezium = 1.1 * 0.8
Area of the trapezium = 0.88m²
Answer:
12.2
Step-by-step explanation: