Somewhere around 5, options please? its more common since then you think.
Answer:
Claire is standing at a distance of 485.45 meters to Chloe.
Step-by-step explanation:
The track is a circular with a radius of 100 meters.
The total length of the circular track = length of the circumference of a circle
But, length of the circumference of a circle = 2
r
So that,
total length of the circular track = 2
r
= 2 ×
× 100
= 628.57
The total length of the circular track is 628.57 meters.
Thus,
the distance of Claire to Chloe = total length of the circular track - distance of Chloe to Claire
= 628.57 - 143.12
= 485.45
This means that Claire is standing at a distance of 485.45 meters to Chloe.
Answer:
Step-by-step explanation:
Lets start by labeling the triangle. Lets say the height is x and the base is x-16.
Next, we know the area of the triangle is 96, so we should make an equation. The area (96) of a triangle is (b*h)/2. So lets substitute.
96=[(x-16)*x]/2
Now, we should simplify the equation. Let us start by moving the /2 to the other side and making it *2.
192=(x-16)*x
Open parenthesis and get
192=x^2-16x
simplify and get
x=24
x is the height so the base must be x-16.
base=8, height=24
Answer:
14
Step-by-step explanation:
Answer:
1/6
Step-by-step explanation:
Given:
- Length of the trough: 9 ft
=> The volume of the trough: V =
* (b * h) (1)
- An isosceles right triangle with hypotenuse 2 feet
=> the other two sides of the triangle is:
= tan(45 degrees) = h/(b/2)
<=> b = 2h substitute in (1), we have:
V =
*(2h *h) = 9
Take derivative of volume with respect to time to find equation for rate of filling the trough
dV/dt = 2 * 9 *h dh/dt = 18h dh/dt
<=> dh/dt = dV/dt /(18h)
As we know that, dV/dt = 2
So, dh/dt = 2 / 18h = 1/9h
<=> V = t * rate = 2 * 2 = 4
But V = 9
<=> 9
= 4
<=> h = 2/3
The rate is the height h feet of the water in the trough changing 2 minutes after the water begins to flow:
dh/dt = 1/(9h) = 1/(9 * 2/3) = 1/6