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ddd [48]
2 years ago
5

{2}^{4} " alt="8( {4}^{2})+ {2}^{4} " align="absmiddle" class="latex-formula">
What is this? does it have the same value as
{12}^{2}
​
Mathematics
1 answer:
miss Akunina [59]2 years ago
4 0
Yes it has the same value

They are exponents so it would be 8 times (4*4) + (2*2*2*2)

The exponent is how many times u multiple itself
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Find the distance between the points (3, -1) and (4, 6).
andrezito [222]

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{3}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[4-3]^2+[6-(-1)]^2}\implies d=\sqrt{(4-3)^2+(6+1)^2} \\\\\\ d=\sqrt{50}\implies d\approx 7.07

6 0
3 years ago
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Henry is making a corn grits recipe that calls for 1/4 cup of corn grits for every 1/2 cup of water. How much water will he need
Archy [21]

Method 1:

\begin{array}{ccc}\dfrac{1}{4}\ \text{cup of corn}&-&\dfrac{1}{2}\ \text{cup of water}\\\\1\dfrac{1}{2}=\dfrac{3}{2}\ \text{cup of corn}&-&x\ \text{cup of water}\end{array}\qquad\text{cross multiply}\\\\\\\dfrac{1}{4}\cdot x=\dfrac{3}{2}\cdot\dfrac{1}{2}\\\\\dfrac{1}{4}x=\dfrac{3}{4}\qquad\text{multiply both sides by 4}\\\\\boxed{x=3}

<h3>Answer: Henry will need 3 cups of water.</h3>

Method 2:

\begin{matrix}\dfrac{1}{4}\ \text{cup of corn}&-&\dfrac{1}{2}\ \text{cup of water}&|\text{multiply both sides by 2}\\\\\dfrac{1}{2}\ \text{cup of corn}&-&1\ \text{cup of water}&|\text{multiply both sides by 2}\\\\1\ \text{cup of corn}&-&2\ \text{cup of water}&|\end{matrix}

\begin{matrix}\left(\dfrac{1}{2}+1\right)\ \text{cups of corn}&-&(1+2)\ \text{cups of water}\\\\1\dfrac{1}{2}\ \text{cups of corn}&-&3\ \text{cups of water}\end{matrix}

<h3>Answer: Henry will need 3 cups of water.</h3>
5 0
3 years ago
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Which value of y makes the equation 13 – y = 17 true?
Volgvan
Answer = B
Working = 13-(-4) = 17
3 0
3 years ago
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How many factors in the expression 8(x +4) (y +4) (z 2 + 4z + 7) have exactly two terms?
Anna11 [10]
From the expression <span>8(x +4) (y +4) (z 2 + 4z + 7),
</span>the factors are 8, (x+4), (y+4), <span>(z^2 + 4z + 7) since each of these factors, when you divide that to the whole expression won't give a remainder</span>
4 0
3 years ago
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Explain why the quadratic relation y=2x^2+3x+5 would have no zeros
alex41 [277]

Complete the square to rewrite the quadratic:

2 <em>x</em>² + 3 <em>x</em> + 5 = 2 (<em>x</em>² + 3/2 <em>x</em>) + 5

... = 2 (<em>x</em>² + 3/2 <em>x</em> + 9/16 - 9/16) + 5

... = 2 (<em>x</em>² + 3/2 <em>x</em> + (3/4)²) + 5 - 9/8

... = 2 (<em>x</em> + 3/4)² + 31/8

Any real number squared becomes non-negative, so the quadratic expression has a minimum value of 31/8, which is greater than 0, and so there are no (real) <em>x</em> for which <em>y</em> = 0.

5 0
3 years ago
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