Answer:
First Olympic held in year 1896.
Step-by-step explanation:
Number of Olympiad held in Rio = XXXI = 31st
Difference of years in two consecutive Olympiads = 4 years
Number of years spent in 31 Olympiads can be calculated by,
Number of years spent = (n - 1)d
Here n = number of Olympiads held
d = difference between two consecutive Olympiads
Number of years spent till 31st Olympiads = (31 - 1)×4
= 120 years
Therefore, 1st Olympiad held in the year = 2016 - 120
= 1896
Should be 32 days. I say that because half of 1 gallon is drank a day so multiple 16x2=32
8x-10y=-23
9x+10y=-16
(8x+9x)+(10y-10y)=(-23+(-16))
17x+0y=-39
x=-39/17
8(-39/17)-10y=-23
-312/17-10y=-23
-10y=-23+312/17
-10y=-79/17
y=79/170
Answer: 2 hours
Step-by-step explanation:
Given : Working alone at their respective constant rates, machine A and machine B can fill a certain order in 3 hours and 6 hours, respectively.
Let t be the time taken by both of them working together.
Then, according to the question, we have
![\dfrac{1}{t}=\dfrac{1}{3}+\dfrac{1}{6}\\\\\Rightarrow\dfrac{1}{t}=\dfrac{2+1}{6}\ \ [\because\ L.C.M. (3,6)=6]\\\\\Rightarrow\dfrac{1}{t}=\dfrac{3}{6}=\dfrac{1}{2}\\\\\Rightarrow t=2](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bt%7D%3D%5Cdfrac%7B1%7D%7B3%7D%2B%5Cdfrac%7B1%7D%7B6%7D%5C%5C%5C%5C%5CRightarrow%5Cdfrac%7B1%7D%7Bt%7D%3D%5Cdfrac%7B2%2B1%7D%7B6%7D%5C%20%5C%20%5B%5Cbecause%5C%20L.C.M.%20%283%2C6%29%3D6%5D%5C%5C%5C%5C%5CRightarrow%5Cdfrac%7B1%7D%7Bt%7D%3D%5Cdfrac%7B3%7D%7B6%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5C%5C%5C%5C%5CRightarrow%20t%3D2)
Hence, it will take 2 hours by the two machines .
