What is the equation for the sum of half a number and two-thirds of the number is less than 14?

Mari has a part time job. She earns $7 an hour. She makes at most $143.50 a week. What is the greatest number of hours that she

Readme [11.4K]

591.928571 is your answer

8 0

3 years ago

Suppose that, in the past, 40% of all adults favored capital punishment. Do we have reason to believe that the proportion of adu

Alex_Xolod [135]

Answer:

The p-value of the test is 0.1469 > 0.05, which means that there is no reason to believe that the proportion of adults favoring capital punishment today has increased, using a 0.05 level of significance.

Step-by-step explanation:

Suppose that, in the past, 40% of all adults favored capital punishment. Test if the proportion has increased:

At the null hypothesis, we test if the proportion is still of 40%, that is:

$H_0: p = 0.4$

At the alternative hypothesis, we test if the proportion has increased, that is, is greater than 40%, so:

$H_1: p > 0.4$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.4 is tested at the null hypothesis:

This means that $\mu = 0.4, \sigma = \sqrt{0.4*0.6}$

Random sample of 15 adults, 8 favor capital punishment.

This means that $n = 15, X = \frac{8}{15} = 0.5333$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.5333 - 0.4}{\frac{\sqrt{0.4*0.6}}{\sqrt{15}}}$

$z = 1.05$

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion of 0.5333 or more, which is 1 subtracted by the p-value of z = 1.05.

Looking at the z-table, z = 1.05 has a p-value of 0.8531.

1 - 0.8531 = 0.1469.

The p-value of the test is 0.1469 > 0.05, which means that there is no reason to believe that the proportion of adults favoring capital punishment today has increased, using a 0.05 level of significance.

3 0

3 years ago

6. Adlise Leiber started the day with a bank balance of $343.64.

snow_tiger [21]

Answer:

$123.62

Step-by-step explanation:

85.10 + 23.95 + 8.47 = 117.52

117.52 + 100 + 2.50 = 220.02

$343.64 - $220.02 = $123.62

3 0

3 years ago

Find all the values of x where the tangent line is horizontal.<br> 2x^3+36x^2+192x+12

Afina-wow [57]

At x = -4 and -8
Take the derivative of the given equation to find rate of change of the graph.
f'(x) = 6x^2 + 72x + 192
At a horizontal tangent, f'(x) = 0, so set the equation equal to 0 and solve. Eventually you get x = -4 and -8

3 0

3 years ago

A box contains 19 large marbles and 18 small marbles. Each marble is either green or white. 9 of the large marbles are green, an

pshichka [43]

If a marble is randomly selected from the box, then the probability

that it is small or green is 0.7297

Step-by-step explanation:

A box contains 19 large marbles and 18 small marbles

Each marble is either green or white

9 of the large marbles are green, and 8 of the small marbles are white

If a marble is randomly selected from the box, we need to find the

probability that it is small or green

1. Find P(small) ⇒ P(s)

2.Find P(green) ⇒ P(g)

3. Find P(small and green) ⇒ P(s and g)

4. Use the rule P(small or green) = P(s) + P(g) - P(s and g)

∵ The box contains 19 large marbles and 18 small marbles

∴ The total number of marbles = 19 + 18 = 37

∴ P(s) = $\frac{18}{37}$

∵ There are 8 small white marbles

∵ There are 18 small marbles

∴ The number of small green marbles = 18 - 8 = 10

∴ P(s and g) = $\frac{10}{37}$

∵ There are 9 large green marbles

∵ There are 10 small green marbles

∴ The number of green marbles = 9 + 10 = 19

∴ P(g) = $\frac{19}{37}$

∵ P(small or green) = P(s) + P(g) - P(s and g)

∴ P(small or green) = $\frac{18}{37}+\frac{19}{37}-\frac{10}{37}$

∴ P(small or green) = $\frac{27}{37}$ = 0.7297

If a marble is randomly selected from the box, then the probability

that it is small or green is 0.7297

Learn more:

you can learn more about probability in brainly.com/question/13053309

#Learnwithbrainly

5 0

3 years ago