Vertex (-3,1)
No xinters
Y-inter (0,37)
Answer:
7f/z
Step-by-step explanation:
mat h wAyz
Important: Please use " ^ " to indicate exponentiation:
<span>"f(x) =x^2 to the number of x-intercepts in the graph of g(x) = x^2 +2."
Notes: the graph of f(x) = x^2 is a vertical parabola that opens up. It has its vertex at (0,0). This is the only point at which f(x)=x^2 has a horiz. intercept.
g(x) = x^2 + 2 has a graph that looks the same as that of f(x) = x^2, EXCEPT that the whole graph is moved 2 units UP. This new graph never touches or intersects the x-axis. Therefore, g(x) has NO horiz. intercepts (no x-int.).
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5+4×(8-6) to the 2nd 9×2 to the 2nd equals 9×4 which then equals 36.
Multiply by 2 which is 8x-8y=-80then subtract from 8x-8y=80 you will get 0=160 so that it is no solution. Have a nice day.