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xxTIMURxx [149]
4 years ago
13

For a figure on a coordinate plane with the origin as the center of dilation, if (x, y) ⟶ (ax, ay) and (1.5, 2.0) ⟶ (6.0, 8.0),

what is a?
Mathematics
1 answer:
Gnoma [55]4 years ago
3 0
The correct answer to this question is 4.

In order to solve this problem, first make an image on your mind how the image is dilated.

The coordinate points at first is (1.5, 2.0). 
After dilation from the origin, the points became (6.0, 8.0)

Looking at it in fraction form, (new / old) we have
6.0 / 1.5 = 4.0
8.0 / 2.0 = 4.0

The quotient of each fraction yields to 4.0. This means that a = 4.

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or 

(-3)(2)(-2)
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You get the same answer. 
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4 years ago
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Matthew is 6 feet 2 inches tall. His little cousin is 3 feet 6 inches tall. How much taller is Matthewthen Emma?
Assoli18 [71]
<span>32 inches or 2 feet, 8 inches. </span>
8 0
3 years ago
What is the measure of angle a and angle c ?
hjlf

Answer:

∠A = 40°

∠C = 32°

Step-by-step explanation:

Inscribed angles that intercept the same arc have the same measure.

∠A intercepts the same arc (CD) as ∠B, so has the same measure, 40°.

∠C intercepts the same arc (AB) as ∠D, so has the same measure, 32°.

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4 years ago
Select the correct answer.
olga nikolaevna [1]

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Step-by-step explanation:

x - 7

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3 0
3 years ago
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A page should have perimeter of 42 inches. The printing area within the page
Tamiku [17]

Overall  dimensions of the page in order to maximize the printing area is  page should be 11 inches wide and 10 inches long .

<u>Step-by-step explanation:</u>

We have , A page should have perimeter of 42 inches. The printing area within the page  would be determined by top and bottom margins of 1 inch from each side, and the  left and right margins of 1.5 inches from each side. let's assume  width of the page be x inches  and its length be y inches So,

Perimeter = 42 inches

⇒ 2(x+y) = 42\\x+y = 21\\y = 21-x

width of printed area = x-3  & length of printed area = y-2:

area = length(width)

area = (x-3)(y-2)\\area = (x-3)(21-x-2)\\area = (x-3)(19-x)\\area = -x^{2} + 22x -57

Let's find \frac{d(area)}{dx}:

\frac{d(area)}{dx} = \frac{d(-x^{2}+22x-57)}{dx} = -2x +22 , for area to be maximum \frac{d(area)}{dx}= 0

⇒ -2x+22 = 0\\2x =22\\x=11 inches

And ,

y = 21-x\\y = 21-11\\y = 10 inches

∴ Overall  dimensions of the page in order to maximize the printing area is  page should be 11 inches wide and 10 inches long .

7 0
3 years ago
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