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3 years ago

Which is a solution to the following inequality? MARK ALL THAT APPLY. 5x-10 > 42

Mathematics

2 answers:

Vlada [557]3 years ago

7 0

Answer:

x > 10.4

Step-by-step explanation:

5x - 10 > 42

+10 +10

5x = 52

52÷5 = 10.4

x > 10.4

Alex777 [14]3 years ago

6 0

Answer:

x> 10.4

Step-by-step explanation:

5x-10 > 42

5x>52

x> 10.4

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Find equivalent fractions with a common denomination 2/3 1/2 5/12

aliina [53]

Hi there!

To find equivalent fractions, we need to multiply both the numerator and the denominator by the same number.

These equivalent fractions are the original fractions multiplied by 2/2:

2/3 = 4/6
1/2 = 2/4
5/12 = 10/24

Hope this helps!

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3 years ago

Complete the factorization 3x^2-10x+18

Ratling [72]

The answer is 3x^2 - 10x + 8 = (x-2)(3x-4)

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3 years ago

Read 2 more answers

Select the correct answer. A model rocket was launched from the top of a building. The rocket's approximate height can be modele

garri49 [273]

Answer:

13 seconds.

Step-by-step explanation:

Given

$h = -4.9(t - 13)(t + 2).$

Required

Determine a reasonable solution for t

To do this, we equate h to 0.

$h = -4.9(t - 13)(t + 2).$ becomes

$0 = -4.9(t - 13)(t + 2).$

Divide through by -4.9

$0 = (t - 13)(t + 2).$

Reorder the expression

$(t - 13)(t + 2) = 0.$

Split

$t-13 = 0$ or $t + 2 = 0$

This gives:

$t = 13$ or $t = -2$

But time can't be negative, So:

$t = 13$

6 0

3 years ago

Translate the sentence into an equation. Four times the difference of a number and 5 is 24.

uranmaximum [27]

Correct!!! ♥ good job

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3 years ago

A hemisphere has an area of 256 pi cm^2. What is its volume?

Amanda [17]

$\bf \begin{array}{llll}
\textit{surface area of a sphere}\\\\
A=4\pi r^2
\\\\\\
\textit{a hemisphere is half that}\\\\
A=\cfrac{4\pi r^2}{2}\implies A=2\pi r^2
\end{array}\qquad r=radius
\\\\\\
\textit{now, we know the area is }256\pi \implies 256\pi =2\pi r^2
\\\\\\
\cfrac{256\pi }{2\pi }=r^2\implies \sqrt{128}=r\implies \boxed{8\sqrt{2}=r}
\\\\
-----------------------------\\\\$

$\bf \textit{volume of a sphere}\\\\
V=\cfrac{4}{3}\pi r^3\qquad r=radius
\\\\\\
\textit{a hemisphere is half that}\\\\
V=\cfrac{\frac{4}{3}\pi r^3}{2}\implies V=\cfrac{\frac{4\pi r^3}{3}}{\frac{2}{1}}\implies V=\cfrac{4\pi r^3}{3}\cdot \cfrac{1}{2}
\\\\\\
V=\cfrac{2\pi r^3}{3}
\\\\\\
\textit{now, we know the radius is }8\sqrt{2}\implies V=\cfrac{2\pi (8\sqrt{2})^3}{3}
\\\\\\
V=\cfrac{2\pi (8^3\sqrt{2^3})}{3}\implies V=\cfrac{2\pi \cdot 512\cdot 2\sqrt{2}}{3}
\\\\\\
\boxed{V=\cfrac{2048\pi \sqrt{2}}{3}}$

7 0

4 years ago