Hello,
h(x)'=(f(x)*g(x))'=f'(x)*g(x)+f(x)*g'(x)
h(1)=f'(1)*g(1)+(f(1)*g'(1)=-4*3+4*(-3)=-24
Answer B
The answer is or the slope is D 2/3
Answer:
20
Step-by-step explanation:
When you add them all up and divide by seven, you get 20
Considering the definition of zeros of a function, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.
<h3>Zeros of a function</h3>
The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.
In summary, the roots or zeros of the quadratic function are those values of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.
In a quadratic function that has the form:
f(x)= ax² + bx + c
the zeros or roots are calculated by:

<h3>This case</h3>
The quadratic function is f(x) = x² + 4x +9
Being:
the zeros or roots are calculated as:



and



If the content of the root is negative, the root will have no solution within the set of real numbers. Then
has no solution.
Finally, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.
Learn more about the zeros of a quadratic function:
brainly.com/question/842305
brainly.com/question/14477557
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Answer:
right
Step-by-step explanation: