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3 years ago

Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

son4ous [18]3 years ago

8 0

Answer:

Step-by-step explanation:

The orthocenter of a triangle is the point of intersection of the three altitudes of the triangle.

In an obtuse triangle, two altitudes are completely outside the triangle; therefore, the three altitudes cannot possibly intersect inside the triangle.

Answer: B

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Shop Rite has jeans on sale for 3/10 off. Save More has jeans on sale for 33% off. Which store has a better deal? Explain.

umka21 [38]

save more has a better deal because when you convert 33% into a fraction out of ten it becomes 3.3/10 and shop right is 3/10 so 3.3 is greater than 3.

5 0

3 years ago

Plss help ASAP

Tom [10]

Answer:

5:9

Step-by-step explanation:

There are 5 blue shapes out of 9 total shapes.

8 0

3 years ago

Read 2 more answers

HELP ME PLEASEEE!!!!!!!

melisa1 [442]

Answer:

The answer should be "Outlier".

3 0

3 years ago

What are the solutions to the equation

frosja888 [35]

Answer:

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

Step-by-step explanation:

You have the quadratic function $2x^2-x+1=0$ to find the solutions for this equation we are going to use Bhaskara's Formula.

For the quadratic functions $ax^2+bx+c=0$ with $a\neq 0$ the Bhaskara's Formula is:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}$

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}$

It usually has two solutions.

Then we have $2x^2-x+1=0$ where a=2, b=-1 and c=1. Applying the formula:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}\\\\x_1=\frac{-(-1)+\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_1=\frac{1+\sqrt{1-8} }{4}\\\\x_1=\frac{1+\sqrt{-7} }{4}\\\\x_1=\frac{1+\sqrt{(-1).7} }{4}\\x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}$

Observation: $\sqrt{-1}=i$

$x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}\\\\x_1=\frac{1+i.\sqrt{7}}{4}\\\\x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$

And,

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}\\\\x_2=\frac{-(-1)-\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_2=\frac{1-i.\sqrt{7} }{4}\\\\x_2=\frac{1}{4}-(\frac{\sqrt{7}}{4})i$

Then the correct answer is option C.

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

3 0

3 years ago

The least common multiple of 20,5, and 2.

USPshnik [31]

Answer:

Step-by-step explanation:

the lowest number they can all muliply to is 20

20 x 1 = 20

5 x 4 = 20

2 x 10 = 20

8 0

3 years ago