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zimovet [89]
3 years ago
14

Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
son4ous [18]3 years ago
8 0

Answer:

B

Step-by-step explanation:

The orthocenter of a triangle is the point of intersection of the three altitudes of the triangle.

In an obtuse triangle, two altitudes are completely outside the triangle; therefore, the three altitudes cannot possibly intersect inside the triangle.

Answer: B

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You have $700 to invest in an account and need to have $950 in one year. What interest rate would you need to have in order to r
zhenek [66]

Answer:

136% = 1.36

Step-by-step explanation:

(950-700)/700

=0.3571 (0.36)

Then you have to plus one

0.36+1

=136% or 1.36

4 0
3 years ago
A student draws the net below to show the dimensions of the container that is shaped like a right rectangular prism. What is the
ZanzabumX [31]

Answer:

The correct option is;

D) 62 in²

Step-by-step explanation:

Here we have from the drawing, the dimensions of the right rectangular prism are;

Height = 2 in.

Width = 5 in

Length = 3 in

Therefore the surface area is found as follows;

Surface area of right rectangular prism = 2 × Height × Width + 2 × Height × Length + 2  × Width × Length

Surface area of right rectangular prism = 2 × 2 × 5 + 2 × 2× 3+ 2  × 5× 3 = 20 + 12 + 30 = 62 in².

5 0
3 years ago
I NEED HELP AND IM ON A TIMED TEST
stira [4]

This Question is not Complete

Complete question

The number of absences per student in each of two classes is shown on the dot plots below.

A dot plot titled Number of absences per student in Misses Anderson's class. The number line goes from 0 to 6. There is 1 dot above 0, 3 above 1, 3 above 2, 3 above 3, 1 above 4, and 0 above 5 and 6.

A dot plot titled Number of absences per student in Misses Bergot's class. The number line goes from 0 to 6. There is 1 dot above 0, 1 above 1, 2 above 2, 3 above 3, 2 above 4, 1 above 5, and 1 above 6.

Which statements accurately compare the two data sets? Select three options.

a. The mean number of absences is greater in Mrs. Anderson’s class.

b. The mean number of absences is greater in Mrs. Bergot’s class.

c. There is more variability in Mrs. Anderson’s data set.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Answer:

b. The mean number of absences is greater in Mrs. Bergot’s class.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Step-by-step explanation:

From the above data given in the question and the options given to us, we can observe from the comparison of both the number of absences in Mrs Bergot's class to that in Mrs Anderson's class, there will be a presence of variation in the data of one of the classes and that class happens to be Mrs Bergot's class.

The appropriate statistical tool that we can be used to determine and measure the centre of variability of the data is Mean and Mean Absolute Deviation.

7 0
3 years ago
What is the answer to the question?
ololo11 [35]

Answer:

I think the answer is -25

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Please help I'am very lost on this one thank you all
LUCKY_DIMON [66]
Large rectangles = 2*3*6
medium rectangles = 2*2*6
small rectangles = 2*2*3
surface area = 72 cm^2
8 0
3 years ago
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