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mash [69]
4 years ago
5

Which two charges have the sum of 0

Mathematics
2 answers:
pogonyaev4 years ago
7 0
+7 and -7 as they both cancel each other out
JulsSmile [24]4 years ago
5 0

Third option. They cancel eachother out therefore it'd be 0

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Jordyn drives 10 minutes at 80 mph how far did she drive
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Jordyn drives 10 miles
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An online furniture store sells chairs for $150 each and tables for $550 each. Every day, the store can ship at most 32 pieces o
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Q7. Average of 60 numbers are 55. When 10 more numbers are included, the average of
Nikitich [7]

Answer:

The average of the 10 numbers is 195

Step-by-step explanation:

The average of a set of numbers is the sum of the numbers dividing by their number

  • Average = The sum ÷ The number

∵ The average of 60 numbers is 55

∴ The average = 55

∴ The number = 60

→ Substitute them in the rule above to find the sum of the numbers

∵ 55 = The sum ÷ 60

→ Multiply each side by 60

∴ 3300 = The sum

∴ The sum of the 60 numbers = 3300

∵ 10 more numbers are included

∵ The average of  70 numbers become 75

∴ The average = 75

∴ The number = 70

→ Substitute them in the rule above to find the sum of the numbers

∵ 75 = The sum ÷ 70

→ Multiply each side by 70

∴ 5250 = The sum

∴ The sum of the 70 numbers = 5250

∵ The sum of the 10 numbers that added is the difference between

   the sums of the 60 and 70 numbers

∵ The difference between the sums = 5250 - 3300

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5 0
3 years ago
Given the following trigonometric ratio, enumerate the meaning ratio ​
Likurg_2 [28]

Answer:

The trigonometric ratios are presented below:

\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}

\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}

\cot \theta = \frac{BC}{AC}

\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}

\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}

Step-by-step explanation:

From Trigonometry we know the following definitions for each trigonometric ratio:

Sine

\sin \theta = \frac{y}{h} (1)

Cosine

\cos \theta = \frac{x}{h} (2)

Tangent

\tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{y}{x} (3)

Cotangent

\cot \theta = \frac{\cos \theta}{\sin \theta} = \frac{x}{y} (4)

Secant

\sec \theta = \frac{1}{\cos \theta} = \frac{h}{x} (5)

Cosecant

\csc \theta = \frac{1}{\sin \theta} = \frac{h}{y} (6)

Where:

x - Adjacent leg.

y - Opposite leg.

h - Hypotenuse.

The length of the hypotenuse is determined by the Pythagorean Theorem:

h = \sqrt{x^{2}+y^{2}}

If y = AC and x = BC, then the trigonometric ratios are presented below:

\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}

\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}

\cot \theta = \frac{BC}{AC}

\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}

\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}

6 0
3 years ago
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