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o-na [289]
3 years ago
5

A railway tunnel 147m long is to be bored with a circular cross section of radius 5m.what volume of soil has to be excavated?

Mathematics
1 answer:
skad [1K]3 years ago
8 0
We have to find the volume of the cylinder, where: r = 5 m and h = 147 m.
V = r² h π
V = 5² · 147 · 3.14 = 25 · 147 · 3.14 = 11,539.5 m³
Answer:
11,539.5 m³ of soil has to be excavated.
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Three trigonometric functions for a given angle are shown below. cosecant theta = thirteen-twelfths; secant theta = Negative thi
Kay [80]

Answer:

(–5, 12) is the correct answer.

Step-by-step explanation:

We are given the following values:

cosec\theta = \dfrac{13}{12}\\sec\theta=-\dfrac{13}{5}\\cot\theta =-\dfrac{5}{12}

Now, we know the following identities:

sin \theta = \dfrac{1}{cosec\theta}\\cos \theta = \dfrac{1}{sec\theta}\\tan \theta = \dfrac{1}{cot\theta}

Now, the values are:

sin\theta = \dfrac{12}{13}\\cos\theta=-\dfrac{5}{13}\\tan\theta =-\dfrac{12}{5}

Sine value is positive and cos, tan values are negative.

It can be clearly observed that \theta is in 2nd quadrant.

2nd quadrant means, the value of x will be negative and y will be positive.

Let us have a look at the value of tan\theta:

tan\theta  = \dfrac{Perpendicular}{Base}\\OR\\tan\theta  = \dfrac{y-coordinate}{x-coordinate} = -\dfrac{12}{5}\\\therefore y = 12,\\x = -5

Please refer to the attached image for clear understanding and detailed explanation.

Hence, the correct answer is coordinate (x,y) is (–5, 12)

8 0
2 years ago
The area of a rectangular-shaped garden can be no more than 64 square feet. If the length of the garden is 16 feet, what could b
Klio2033 [76]

Answer:

4 square feet

Step-by-step explanation:

Area = Length * Width

64 = 16 * W.

W = 4.

So, 4 square feet.

Mark me as Brainliest if this is correct! I really appreciate it! :D

8 0
2 years ago
Cause I lowkey suck at math How do I do this
dimaraw [331]
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ycow [4]

Step-by-step explanation:

x²+3x+4=0

x²+3x_ +2=0

x²+3x_2=-2

x²+3x_2+(3x_4)²=-2+(3/4)²

(x+3/4) =-2+9_16

x+3_4 = -32+9__16 =√-23_6

x+3_4 =-√23_4

x = -3+√-23___4

x = -3- √-23___4 , -3+√-23___4 //

Mark my answer as branlist answer

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