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2 years ago

The circumference of a circle is 15pie centimeters. What is the area of the circle in terms

Mathematics

1 answer:

Sedaia [141]2 years ago

3 0

Answer:

176.71 cm

56.25π cm

Step-by-step explanation:

The formula for the circumference of a circle is:

C = πd

Where C is the circumference and d is the diameter

Let's substitute the circumference given into this formula:

C = πd

15π = πd

Now, we can solve this equation for d.

Divide by π on both sides:

15π = πd

/π /π

15 = d

Therefore, the diameter is 15 cm.

We need to find the area. The formula for the area of a circle is:

A = πr²

First, let's find the radius. The radius is half of the diameter, so divide the diameter by 2.

15/2 = 7.5

radius = 7.5 cm

Now, we can solve for the area.

Substitute into the formula for area:

A = πr²

A = π(7.5²)

A = π(56.25)

A ≈ 176.71

Therefore, the area is approximately 176.71 cm, or in terms of pi, 56.25π.

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Answer:

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Step-by-step explanation:

If we have 12 as 40%, we divide it by 2 to get the base value which is 6=20%.

Now we multiply the base by 5 so 20% x 5= 100% and 6 x 5 equals 30. so 100% = 30

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3 years ago

Drew wants to buy exercise equipment that costs $140 and the sales tax is 5.57% what is the total cost of the equipment

Eddi Din [679]

Answer:

$147.80

Step-by-step explanation:

140 x .0557 = 7.80 Tax

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2 years ago

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The width of a rectangle is two-thirds of its length, and its area is 216 square meters. What is the length? 12 m 18 m 27 m

olga55 [171]

Hope this helps you.

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3 years ago

The function f(x)=70n -400 models the profit of the instructor of a guitar class per month, where n is the number of students en

suter [353]

Given:
f(x) = 70n - 400 : equation for monthly profit.
n = number of students enrolled in the guitar class.

70 refers to the amount charged per student.
400 is the fixed expense made by the instructor.

For the instructor to have a profit, the product of 70n must be more than 400.

400/70 = 5.7 or 6

There must be at least 6 students enrolled in class for the instructor to generate profit.

f(x) = 70(6) - 400 = 420 - 400 = 20

1000 = 70n - 400
1000 + 400 = 70n
1400 = 70n
1400/70 = n
20 = n

There must be 20 students enrolled in class for the instructor to earn 1000 in profit.

1000 = 70(20) - 400
1000 = 1400 - 400
1000 = 1000

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3 years ago

Solve the system of equations. <br><br> 10x+y=−20 <br><br> y=2x2−4x−16<br><br> ( , ) and ( , )

Sladkaya [172]

I will go about solving this using the elimination method.

First, convert the equations.

10x + y = -20
4x + y = -12

Second, find the easiest variable to get rid of and get rid of it! (In this case, y) We will subtract to get rid of y.

6x = -8

Third, you want to solve the equation.

6x = -8 (divide by 6)
x = $-1 \frac{1}{3}$

Fourth, solve for y by inserting the answer for x into one of the equations.

10( $-1 \frac{1}{3}$ ) + y = -20
$-13 \frac{1}{3}$ + y = -20 (subtract $-13 \frac{1}{3}$ )
y = $-6 \frac{2}{3}$

The solution for this system of equations is ( $-1 \frac{1}{3}$ , $-6 \frac{2}{3}$ ).

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3 years ago

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