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Zolol [24]
3 years ago
10

(0, -2) Correct or not?

Mathematics
1 answer:
8090 [49]3 years ago
4 0
Make f(x) = y
f(x)= -1/8 (4) ^x+3 +6
y = -1/8 (4) ^x+3 +6
y-intercept is when the function crosses the y-axis, and the y-axis is always where x = 0
y = -1/8 (4) ^x+3 +6
y = -1/8 ( {4}^{0})+9 \\  {(anything)}^{0}  = 1 \\ y = -1/8 (1)+9 = 9 - (1 \div 8)  \\ = 8 \: (7 \div 8)
or was the equation instead:
y = -1/8 ( {4}^{(x + 3)})+6
???????
Because in that case it's totally different, so here goes...
y = -1/8 ( {4}^{(x + 3)})+6 \\ y = -1/8 ( {4}^{(0 + 3)})+6 \\ y = -1/8 ( {4}^{3})+6 \\ y = -1/8 (64)+6
y = -1/1 (8)+6 =  - 8 + 6 =  - 2
Therefore, yes it is correct that the y-intercept lies at the point (0, -2)

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Sqrt(32x^3) - sqrt(16x^3) + root(4,x^3) -sqrt(2x^3)
almond37 [142]

An expression is defined as a set of numbers, variables, and mathematical operations. The simplified version of the given expression is (3√2-2)√x³.

<h3>What is an Expression?</h3>

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

The given expression \sqrt{32x^3} - \sqrt{16x^3} + \sqrt{4x^3} -\sqrt{2x^3} can be simplified as shown below.

\sqrt{32x^3} - \sqrt{16x^3} + \sqrt{4x^3} -\sqrt{2x^3}\\\\=\sqrt{x^3}(\sqrt{32}-\sqrt{16}+\sqrt{4}-\sqrt{2}})\\\\= \sqrt{x^3} (4\sqrt{2}-4+2-\sqrt2)\\\\= \sqrt{x^3} (3\sqrt{2}-2)

Hence, The simplified version of the given expression is (3√2-2)√x³.

Learn more about Expression:

brainly.com/question/13947055

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7 0
2 years ago
Brainlist for correct answer =]
Vesnalui [34]

Answer:

4

Step-by-step explanation:

The mode is the number that appears the most!!!!

Now lets solve :)

2, 2, 3, 3, 4, 4, 4, 4,

There are 2 2s.

There are 2 3s.

There are 4 4s.

The mode is 4!!! :)

Have an amazing day!!

Plese rate and mark brainliest!!

5 0
2 years ago
Read 2 more answers
Please show work thank you
sasho [114]
3 x3 = 9 4 x 3 =12   6 x 2 = 18  3 x
6 0
3 years ago
Solve for z, wz-4/ 5z
saw5 [17]

x=\dfrac{wz-4}{5z}\\\\5xz=wz-4\\\\5xz-wz=-4\\\\z(5x-w)=-4\\\\z=-\dfrac{4}{5x-w}

7 0
3 years ago
If you say that you can help me with homework then why can't I make a code to join and I had to pick one to send this sincerely,
Nataly_w [17]

Answer:

WHAT!!!!!!!

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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