Make f(x) = y f(x)= -1/8 (4) ^x+3 +6 y = -1/8 (4) ^x+3 +6 y-intercept is when the function crosses the y-axis, and the y-axis is always where x = 0 y = -1/8 (4) ^x+3 +6 or was the equation instead: ??????? Because in that case it's totally different, so here goes... Therefore, yes it is correct that the y-intercept lies at the point (0, -2)