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Zolol [24]
3 years ago
10

(0, -2) Correct or not?

Mathematics
1 answer:
8090 [49]3 years ago
4 0
Make f(x) = y
f(x)= -1/8 (4) ^x+3 +6
y = -1/8 (4) ^x+3 +6
y-intercept is when the function crosses the y-axis, and the y-axis is always where x = 0
y = -1/8 (4) ^x+3 +6
y = -1/8 ( {4}^{0})+9 \\  {(anything)}^{0}  = 1 \\ y = -1/8 (1)+9 = 9 - (1 \div 8)  \\ = 8 \: (7 \div 8)
or was the equation instead:
y = -1/8 ( {4}^{(x + 3)})+6
???????
Because in that case it's totally different, so here goes...
y = -1/8 ( {4}^{(x + 3)})+6 \\ y = -1/8 ( {4}^{(0 + 3)})+6 \\ y = -1/8 ( {4}^{3})+6 \\ y = -1/8 (64)+6
y = -1/1 (8)+6 =  - 8 + 6 =  - 2
Therefore, yes it is correct that the y-intercept lies at the point (0, -2)

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