Answer:
I think it will
Explanation:
because we are very rebellious and like Takis with ketchup I love ice cream with mayonnaise<3
Answer:
See the code below and the algorithm explanation on the figure.
Explanation:
The explanation in order to get the answer is given on the figure below.
Solving this problem with C. The program is given below:
#include <stdio.h>
int main(void) {
int n, Even=0, Odd=0, Zeros=0;
for (;;) {
printf("\nEnter the value the value that you want to check(remember just integers): ");
//IF we input a non-numeric character the code end;
if (scanf("%d", &n) != 1) break;
if (n == 0) {
Zeros++;
}
else {
if (n % 2) {
Even++;
}
else {
Odd++;
}
}
}
printf("for this case we have %d even, %d odd, and %d zero values.", Even, Odd, Zeros);
return 0;
}
When someone asks that do not answer or say you do not feel comfortable telling them
Answer:
// here is code in C++.
#include <bits/stdc++.h>
using namespace std;
// recursive function to find sum from 1 to n
int recur_Sum(int n)
{ // base condition
if (n <= 1)
return n;
// recursive call
return n + recur_Sum(n - 1);
}
// main function
int main()
{
// variables
int n;
cout<<"Enter a number:";
// read the number
cin>>n;
// print the sum
cout<<"Sum of first "<<n<<" integer from 1 to "<<n<<" is:"<<recur_Sum(n);
return 0;
}
Explanation:
Read a number from user and assign it to variable "n".Call function recur_Sum() with parameter "n".This function will recursively call itself and find the Sum of first n numbers from 1 to n.Then function will return the sum.
Output:
Enter a number:10
Sum of first 10 integer from 1 to 10 is:55
