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aleksandrvk [35]
3 years ago
8

Using direct mapping, consider a 16-bit memory addresses, and a cache with 64 blocks, where each block is 8 bytes. What is the s

ize of offset, block, and tag
Computers and Technology
1 answer:
spin [16.1K]3 years ago
4 0

Answer:

Tag          Block             Offset

 7               6                   3

Explanation:

Using direct mapping hashing:

Memory address size = 16 bits

Number of cache blocks = 64

Size of each block = 8 bytes

Thus;

Offest field = size of each block = 2^{3} = 3 bits

Number of blocks = 64 = 2

Thus, the index field is = 2^{6} = 6 bits of block

Tag filed is of size = 16 - (3+6) = 7 bits of tag

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