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miss Akunina [59]
3 years ago
9

Imagine a network with two routers that are connected with a point-to-point HDLC serial link. Each router has an Ethernet, with

PC1 sharing the Ethernet with Router1, and PC2 sharing the Ethernet with Router2. When PC1 sends data to PC2, which of the following is true?
a. Router1 strips the Ethernet header and trailer off the frame received from PC1, never to be used again.
b. Router1 encapsulates the Ethernet frame inside an HDLC header and sends the frame to Router2, which extracts the Ethernet frame for forwarding to PC2.
c. Router1 strips the Ethernet header and trailer off the frame received from PC1, which is exactly re-created by R2 before forwarding data to PC2.
d. Router1 removes the Ethernet, IP, and TCP headers and rebuilds the appropriate headers before forwarding the packet to Router2.
Computers and Technology
1 answer:
photoshop1234 [79]3 years ago
3 0

Answer:

The correct option of the following question is a.).

Explanation:

The PC1 will send the Ethernet frames to the Router1, with the PC1's MAC address as source address and the Router1's MAC address as destination address. The Router1 will removes an encapsulated the IP packets from that Ethernet frames, discarding frames header and the trailer. The Router1 will be forward IP packets by the first an encapsulating it's inside the HDLC frames, but the Router1 will not an encapsulate Ethernet frames in the HDLC frames, but rather than an IP packets. The Router2 will be deencapsulate the IP packets from HDLC frames and forward onto Ethernet Local Area Network and adding the new Ethernet headers and the trailer, but this is the header will be different. It will the list Router2's MAC address as source address and the PC2's MAC address as destination address.

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A painting company has determined that for every 115 square feet or wall space, one gallon of paint and eight hours of labor wil
Kay [80]

The program to calculate the total paint cost and other values is given below.

#include <iostream>

using namespace std;

int main() {  

 int rooms, laborChrg = 18;

 float paintChrg;

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 float paintReq, laborHrs, paintCost, laborCost, totalCost, totalsqft=0;  

 cout<<"Enter the number of rooms to be painted "<<endl;

 cin>>rooms;  

 for(int i=0; i <= rooms; i++)

 {

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 cin>>feetPerRoom[i];  

 // shortcut operator which is equivalent to totalsqft = totalsqft +     feetPerRoom[i];

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 }  

 cout<<"Enter the cost of the paint per gallon "<<endl;

 cin>>paintChrg;  

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 cout<<"The number of gallons of paint required "<<paintReq<<endl;

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}

Explanation:

The header files for input and output are imported.

#include <iostream>

using namespace std;

All the variables are taken as float except labour charge per hour and number of rooms.

The user is asked to input the number of rooms to be painted. An array holds the square feet in each room to be painted.

cout<<"Enter the number of rooms to be painted "<<endl;

cin>>rooms;  

for(int i=0; i <= rooms; i++)

{

cout<<"Enter the square feet in room "<<endl;

cin>>feetPerRoom[i];  

totalsqft += feetPerRoom[i];

}  

The above code asks for square feet in each room and calculates the total square feet to be painted simultaneously.

All the data to be displayed is calculated based on the values of labor charge per hour and gallons of paint needed, given in the question.

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laborCost = laborHrs * laborChrg;

paintReq = totalsqft/115;

paintCost = paintReq * paintChrg;

totalCost = laborCost + paintCost;

All the calculated values are displayed in the mentioned order.

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Answer:

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