Answer:
10. 7n - 1 < -8
Isolate the variable, n. Do the opposite of PEMDAS. Treat the < as equal sign, what you do to one side, you do to the other. First, add 1 to both sides:
7n - 1 (+1) < - 8 (+1)
7n < - 8 + 1
7n < - 7
Isolate the variable, n. Divide 7 from both sides:
(7n)/7 < (-7)/7
n < -7/7
n < -1
n < -1 is your answer.
11. 3 > -7v + 4v
Combine like terms, then isolate the variable, v. First, add -7v and 4v together.
3 > (-7v + 4v)
3 > (4v - 7v)
3 > (-3v)
Isolate the variable, v. Divide -3 from both sides. Note that since you are dividing a negative number, you must flip the sign:
(3)/-3 > (-3v)/-3
3/-3 > v
-1 < v
v > -1 is your answer.
~
What kind of problems or what are you trying to ask?
Answer:
![\large\boxed{(2b+3)\times(5b-1)\times(5b+1)}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%282b%2B3%29%5Ctimes%285b-1%29%5Ctimes%285b%2B1%29%7D)
Step-by-step explanation:
The formula of a volume of a rectangular box:
![V=lwh](https://tex.z-dn.net/?f=V%3Dlwh)
<em>l</em><em> - lenght</em>
<em>w</em><em> - width</em>
<em>h</em><em> - height</em>
![V=50b^3+75b^2-2b-3=25b^2(2b+3)-1(2b+3)\\\\=(2b+3)(25b^2-1)=(2b+3)(5^2b^2-1^2)\\\\=(2b+3)\bigg((5b)^2-1^2\bigg)\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=(2b+3)(5b-1)(5b+1)](https://tex.z-dn.net/?f=V%3D50b%5E3%2B75b%5E2-2b-3%3D25b%5E2%282b%2B3%29-1%282b%2B3%29%5C%5C%5C%5C%3D%282b%2B3%29%2825b%5E2-1%29%3D%282b%2B3%29%285%5E2b%5E2-1%5E2%29%5C%5C%5C%5C%3D%282b%2B3%29%5Cbigg%28%285b%29%5E2-1%5E2%5Cbigg%29%5Cqquad%5Ctext%7Buse%7D%5C%20a%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5C%5C%5C%5C%3D%282b%2B3%29%285b-1%29%285b%2B1%29)
Therefore the dinemsions of thisp prism are:
![(2b+3)\times(5b-1)\times(5b+1)](https://tex.z-dn.net/?f=%282b%2B3%29%5Ctimes%285b-1%29%5Ctimes%285b%2B1%29)
I would say 36.8
But I am it sure