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juin [17]
3 years ago
8

A submarine dives 280 feet below the water surface. It then rises back up to wards the surface at 55 feet per minute for 5 minut

es. Where is the submarine after it rises towards the water's surface for 5 minutes
Mathematics
1 answer:
Lapatulllka [165]3 years ago
8 0
The submarine is 5 feet below the water surface.
-280+55(5)=-5
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Step-by-step explanation:

Given

distance crawled by the snail = 6cm = 0.06m

Time taken = 0.75minutes = 0.75*60

Time taken = 45secs

Required

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Speed of the snail = distance/time;

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Speed of the snail = 0.00133m/s

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I need help pls step by step i will really appreciate pls also l will mark you the brainly if you did !
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1. 2

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Step-by-step explanation:

Remember that \frac{\sqrt{a}}{\sqrt{b}}=\sqrt{\frac{a}{b} }, and \frac{a}{\sqrt{b}}=\frac{a}{\sqrt{b}}*\frac{\sqrt{b}}{\sqrt{b}}=\frac{a\sqrt{b}}{b}

1. \frac{\sqrt{48}}{\sqrt{12} }= \sqrt{\frac{48}{12} }=\sqrt{4}=2

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3. \frac{48}{\sqrt{6}}= \frac{48}{\sqrt{6}}* \frac{\sqrt{6}}{\sqrt{6}}= \frac{48\sqrt{6}}{6}=8\sqrt{6}

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Question 13 letter A and B
dybincka [34]
A) 2.50/5= 0.5,
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