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Katyanochek1 [597]

4 years ago

12

Y = x^2 - 8x + 15 line of symmetry

1 answer:

lyudmila [28]4 years ago

8 0

If you are solving for y, your answer is -1.
First, x=4 so plug in the 4 in every into every x.
Second, 4^2 is 16. 8(4) is 32.
Third, 16 - 32 + 15= -1

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Which expressions are equivalint to 3x +2(x - 1) -4

Lerok [7]

Answer:

A. 3x +2(x - 1) -4 and B. 5x-6

Step-by-step explanation:

One of the answers is letter A because its the same exact expression as stated in the question. The other answer is B because of the distribution property you multiple x by 2 and multiply -1 by 2. This now gives us the expression 3x+2x-2-4. Now we add/subtract like terms and that gives the the answer 5x-6. I hope this helps.

4 0

3 years ago

Read 2 more answers

Explain the relationship between the two 5's in the number 455.721

Pie

Well for this one just make it 455 its 55 so tens and ones colloum

3 0

4 years ago

What is the value of x if 5ax+2a equals 9a?

vova2212 [387]

5ax+2a=9a
5ax+2a-2a=9a-2a
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5 0

3 years ago

Suppose a certain population satisfies the logistic equation given by dP

Ksenya-84 [330]

Answer:

The population when t = 3 is 10.

Step-by-step explanation:

Suppose a certain population satisfies the logistic equation given by

$\frac{dP}{dt}=10P-P^2$

with P(0)=1. We need to find the population when t=3.

Using variable separable method we get

$\frac{dP}{10P-P^2}=dt$

Integrate both sides.

$\int \frac{dP}{10P-P^2}=\int dt$ .... (1)

Using partial fraction

$\frac{1}{P(10-P)}=\frac{A}{P}+\frac{B}{(10-P)}$

$A=\frac{1}{10},B=\frac{1}{10}$

Using these values the equation (1) can be written as

$\int (\frac{1}{10P}+\frac{1}{10(10-P)})dP=\int dt$

$\int \frac{dP}{10P}+\int \frac{dP}{10(10-P)}=\int dt$

On simplification we get

$\frac{1}{10}\ln P-\frac{1}{10}\ln (10-P)=t+C$

$\frac{1}{10}(\ln \frac{P}{10-P})=t+C$

We have P(0)=1

Substitute t=0 and P=1 in above equation.

$\frac{1}{10}(\ln \frac{1}{10-1})=0+C$

$\frac{1}{10}(\ln \frac{1}{9})=C$

The required equation is

$\frac{1}{10}(\ln \frac{P}{10-P})=t+\frac{1}{10}(\ln \frac{1}{9})$

Multiply both sides by 10.

$\ln \frac{P}{10-P}=10t+\ln \frac{1}{9}$

$e^{\ln \frac{P}{10-P}}=e^{10t+\ln \frac{1}{9}}$

$\frac{P}{10-P}=\frac{1}{9}e^{10t}$

Reciprocal it

$\dfrac{10-P}{P}=9e^{-10t}$

$P(t)=\dfrac{10}{1+9e^{-10t}}$

The population when t = 3 is

$P(3)=\dfrac{10}{1+9e^{-10\cdot 3}}$

Using calculator,

$P=9.999\approx 10$

Therefore, the population when t = 3 is 10.

8 0

3 years ago

If the family plans to move to their retirement home in 10 years, which pool would be more cost effective to install? How do

densk [106]

Answer:

Step-by-step explanation:

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3 years ago