Answer:
c) 8.6
Step-by-step explanation:
Take the coordinates of the two points.
(0,8) and (7,3)
Formula:
√(x₁ - x₂)² + (y₁ - y₂)²
Substitute:
√(0 - 7)² + (8 - 3)²
√(-7)² + (5)²
√(49) + (25)
√(74) ≈ 8.6
<h3>
Answer: 9+0 = 9</h3>
The additive identity is 0. If you add 0 to any number, then you get the same number as a result. In general, x+0 = x where x is a place holder for any number. For this problem, x = 9 so that's how 9+0 = 9.
Answer:
<u>Triangle ABC and triangle MNO</u> are congruent. A <u>Rotation</u> is a single rigid transformation that maps the two congruent triangles.
Step-by-step explanation:
ΔABC has vertices at A(12, 8), B(4,8), and C(4, 14).
- length of AB = √[(12-4)² + (8-8)²] = 8
- length of AC = √[(12-4)² + (8-14)²] = 10
- length of CB = √[(4-4)² + (8-14)²] = 6
ΔMNO has vertices at M(4, 16), N(4,8), and O(-2,8).
- length of MN = √[(4-4)² + (16-8)²] = 8
- length of MO = √[(4+2)² + (16-8)²] = 10
- length of NO = √[(4+2)² + (8-8)²] = 6
Therefore:
and ΔABC ≅ ΔMNO by SSS postulate.
In the picture attached, both triangles are shown. It can be seen that counterclockwise rotation of ΔABC around vertex B would map ΔABC into the ΔMNO.
complette the square to get vertex form or y=a(x-h)^2+k
(h,k) is vertex
1. group x terms, so for y=ax^2+bx+c, do y=(ax^2+bx)+c
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<span>
</span>
2, factor out the leading coefinet (constant in front of the x^2 term), basicallly factor out a
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</span>
3. take 1/2 of the linear coefient (number in
front of the x), and square it ,then add negative and positive of it
inside parnthases
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4. complete the squre and expand
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so
y=-1/4x^2+4x-19
group
y=(-1/4x^2+4x)-19
undistribute -1/4
y=-1/4(x^2-16x)-19
take 1/2 of -16 and squer it to get 64 then add neg and pos inside
y=-1/4(x^2-16x+64-64)-19
factorperfect square
y=-1/4((x-8)^2-64)-19
expand
y=-1/4(x-8)^2+16-19
y=-1/4(x-8)^2-3
vertex is (8,-3)
Answer:
2.2
Step-by-step explanation:
Find square root of sample size then divid it by your standard deviation
