IF the estimates are 100% accurate, then the maximum volume of concrete is the product of the maximum dimensions, namely
Vmax=18.32*12.22*0.55=123.13 m^3
and the minimum volume of concrete is the product of the minimum dimensions
Vmin=18.28*12.18*0.45=100.19 m^3
the uncertainty is therefore 123.13-100.19=22.94 m^3
On the practical side, to this uncertainty must be added to
- squareness of the formwork
- evenness of the surface of the crushed stones on which the foundation sits on
- excess of concrete delivered by the truck
- volume of air bubbles trapped in the the concrete, ...
I divided 6 by 156 and I got 0.0384615385 that's what I got
Y = mx + b
m = slope of the line
b= y-intercept
Since you are given the point (4,1/3), the y-value is 1/3.
So plug in the numbers and solve for b:
(1/3)= (3/4)*(4) + b
After you solve the equation for b, you should get -2 2/3 or -8/3
No rewrite the equation with the y-intercept, b.
y = (3/4 x) - (8/3)
96 fl oz is equal to 12 c, while 13 c is equal to 104 fl oz, meaning 13 c is greater.
