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ladessa [460]
2 years ago
15

The rate of decomposition of acetaldehyde, CH_3 CHO(g), into CH_4(g) and CO(g) in the presence of I_2(g) at 800 K follows the ra

te law rate of reaction = k[CH_3 CHO][I_2] The decomposition is believed to occur by the following two-step mechanism: step 1: CH_3 CHO(g) + I_2(g) rightarrow CH_3 I(g) + Hl(g)+ CO(g) step 2: CH_3 l (g) + HI(g) rightarrow CH_4 (g) + I_2 (g)
Which species is the catalyst for the overall reaction?
Which step in the proposed mechanism is most likely the rate-limiting step?
Chemistry
1 answer:
FrozenT [24]2 years ago
5 0

Answer:

Explanation:

Catalyst is I2 . Because I2 is reacted with starting material in step 1 and generated in second step

Rate limiting step is step 1. Because in rate equation CH3CHO and I2 is mentioned. Hence the overall rate of reaction is depending CH3CHO and I2. Rate limiting step is step 1

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Answer:

B

Explanation:

4 0
3 years ago
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Draw the other possible resonance structure of each organic ion. In each case, draw the structure that minimizes formal charges.
pshichka [43]

Three resonance structures  can be drawn for the allyl cation while two resonance structures can be drawn for the amidate ion.

Sometimes, we cannot fully describe the bonding in a chemical specie using a single chemical structure. In such cases, we have to use a number of structures which cooperatively represent the actual bonding in the molecule. These structures are called resonance or canonical structures.

The resonance structures of the allyl cation and the amidate ion are shown in the images attached to this answer. These structures show the different bonding extremes in these organic ions.

Learn more: brainly.com/question/4933048

7 0
2 years ago
NaOH is a strong base. Which two ions do you expect to find in a solution of NaOH?
Elena L [17]
NaOH will dissociate as Na+ and OH- in the solution.
5 0
2 years ago
16.4 mL of 0.135 M NaOH is used to neutralize 46.9 mL of HCl. The concentration of the HCl solution is ____ M (3 decimal places)
marshall27 [118]

The concentration of the HCl solution is 0.047 M.

Explanation:

Data given about acid and base:

volume of acid Vacid = 46.9 ml

molarity of acid =?

volume of the base (NaOH) = 16.4 ml

molarity of the base = 0.135 M

To know the concentration of the acid in this reaction, the formula used in titration  is used. It is

Macid X Vacid = Mbase X Vbase

the formula is rewritten as:

Macid = \frac{Mbase X Vbase}{Vacid}

putting the values in the equation:

Macid = \frac{0.135 X 16.4}{46.9}

          = 0.047 M

the concentration of the acid i.e HCl in the solution is of 0.047 M.

5 0
3 years ago
How much heat is required to raise the temperature of 50.0g of water 13°C<br>​
N76 [4]

Answer:one gram by 1oC

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