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ladessa [460]
3 years ago
15

The rate of decomposition of acetaldehyde, CH_3 CHO(g), into CH_4(g) and CO(g) in the presence of I_2(g) at 800 K follows the ra

te law rate of reaction = k[CH_3 CHO][I_2] The decomposition is believed to occur by the following two-step mechanism: step 1: CH_3 CHO(g) + I_2(g) rightarrow CH_3 I(g) + Hl(g)+ CO(g) step 2: CH_3 l (g) + HI(g) rightarrow CH_4 (g) + I_2 (g)
Which species is the catalyst for the overall reaction?
Which step in the proposed mechanism is most likely the rate-limiting step?
Chemistry
1 answer:
FrozenT [24]3 years ago
5 0

Answer:

Explanation:

Catalyst is I2 . Because I2 is reacted with starting material in step 1 and generated in second step

Rate limiting step is step 1. Because in rate equation CH3CHO and I2 is mentioned. Hence the overall rate of reaction is depending CH3CHO and I2. Rate limiting step is step 1

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Also, CO2 is a pure substance because it is natural and cannot be broken down easily or separated by physical methods.

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