Answer:
f(-6) = 1/64
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Functions
- Function Notation
- Exponential Rule [Rewrite]:

Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 2ˣ
f(-6) is x = -6 for function f(x)
<u>Step 2: Evaluate</u>
- Substitute in <em>x</em> [Function]: f(-6) = 2⁻⁶
- Exponential Rule - Rewrite: f(-6) = 1/2⁶
- Exponents: f(-6) = 1/64
Answer:
x = -3, 6
Step-by-step explanation:
First, add 18 to both sides
x² - 3x - 18 = 0
+ 18 + 18
x² - 3x = 18
Add 9/4 to both sides because that is the square of half of -3
x² - 3x + 9/4 = 18 + 9/4
Multiply both sides by 4 to get rid of the fractions
(x² - 3x + 9/4 = 18 + 9/4)4
4x² - 12x + 9 = 72 + 9 = 81
Factor the left side of the equation
(2x - 3)² = 81
√(2x - 3)² = √81
Because of the square root, this will result in a positive number and a negative number
2x - 3 = 9
2x - 3 = -9
For both equations, add 3 to both sides then divide by 2
2x - 3 = 9
+ 3 +3
2x = 12
2x/2 = 12/2
x = 6
2x - 3 = -9
+ 3 + 3
2x = -6
x = -3
Answer: the answer is b.
r = 0 means that there is not a linear relationship between both variables, but there are other types of relationships that can be happening here.
you for example can have a quadratic relation or something weirder.
The fraction of the girls signed up to play outfield is 
<em><u>Solution:</u></em>
Given that Two fifths of the girls in school signed up to play softball
An equal number of girls signed up to play pitcher, infield and outfield
So there are 3 equal groups formed from two fifth
This means that we could divide the 2/5 initial group into 3 equal smaller groups for each play pitcher, infield and outfield
Therefore, fraction of the girls signed up to play outfield is found by dividing
by 3

Thus fraction of the girls signed up to play outfield is 