Answer:
The ratio of the lateral sides and perimeters = the ratio of square root of their areas
Then, the ratio of the sides and the perimeters is 6:5 or if this is wrong it it is 5:6
if this helps plz mark as brainliest
You cannot assume the angles add to 90, but you know since BD is an angle bisector that ABD is equal to DBC, or x-5=2x-6
x=1. this is the correct solution to the equation but gives negative angles when plugged in which isn't possible. there must be something wrong work the question
Answer:
C) 7
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Work Shown:
Use the slope formula
m = (y2-y1)/(x2-x1)
Plug in the given slope we want m = -5/3 and also the coordinates of the points. Then isolate r
m = (y2-y1)/(x2-x1)
-5/3 = (2-r)/(r-4)
-5(r-4) = 3(2-r) .... cross multiplying
-5r+20 = 6-3r
-5r+20+5r = 6-3r+5r .... adding 5 to both sides
20 = 6+2r
20-6 = 6+2r-6 ....subtracting 6 from both sides
14 = 2r
2r = 14
2r/2 = 14/2 .... dividing both sides by 2
r = 7
The slope of the line through (4,7) and (7,2) should be -5/3, let's check that
m = (y2-y1)/(x2-x1)
m = (2-7)/(7-4)
m = -5/3
The answer is confirmed
Answer:
The value of r=
The value of x=
Step-by-step explanation:
Given that,
A) 
Now,
8(2r-2)=9(7r+10)
16r-16=63r+90
-16-90=63r-16r
-(16+90)=47r
-106=47r
r=
B) 
Now,
5(x+5)=9[3(x-2)-1]
5x+25=9[3x-6-1]
5x+25=9[3x-7]
5x+25=27x-63
25+63=27x+5x
83=32x
x=
The distance between P and Q is 10 units. hope this helps have a nice day
