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den301095 [7]
3 years ago
9

What is the slope and y-intercept? write the equation. also sorry it’s so late

Mathematics
2 answers:
Crank3 years ago
7 0

(y2-y1)/(x2-x1)

19-10=9

6-3=3

9/3=3

slope: 3

y-int: 1

y=3x+1

hammer [34]3 years ago
3 0

Answer:

Can u show the whole question

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5. <br> please choose the CORRECT answer!! thank you so much
andrezito [222]
The solutions are where these two functions intersect, that is, at x = -4 and x = -6. The answer is C.
6 0
3 years ago
PLEASE HELP?! <br><br> Polygon LMNOP ~ Polygon QRSTU What is TU?
ycow [4]

Answer:

The answer is B.

Step-by-step explanation:

9 : 12 = 3 : 4

12 : 16 = 3 : 4

6 0
3 years ago
Read 2 more answers
J'K'L'M' is a translation of JKLM by vector (-6/2). What are the coordinates of K'? What are the coordinates of M'?
pochemuha

By applying the concept of <em>rigid</em> transformation and the equation of translation we conclude that the coordinates of points K' and M' are (-2, 3) and (-4, 1).

<h3>How to apply a translation to a point on a Cartesian plane</h3>

<em>Rigid</em> transformations are transformations applied onto <em>geometric</em> loci such that Euclidean distance is conserved at every point of the loci. Translations are an example of <em>rigid</em> transformations, whose formula is defined by the following expression:

P'(x, y) = P(x, y) + \vec v     (1)

Where:

  • P(x, y) - Original point
  • P'(x, y) - Resulting point
  • \vec v - Translation vector

If we know that K(x, y) = (4, 1), M(x, y) = (2, -1) and \vec v = (-6, 2), then the coordinates of points K' and M' are:

Point K'

K'(x, y) = (4, 1) + (-6, 2)

K'(x, y) = (-2, 3)

Point M'

M'(x, y) = (2, -1) + (-6, 2)

M'(x, y) = (-4, 1)

By applying the concept of <em>rigid</em> transformation and the equation of translation we conclude that the coordinates of points K' and M' are (-2, 3) and (-4, 1).

To learn more on translations: brainly.com/question/17485121

#SPJ1

7 0
2 years ago
HELP ME BRAIN NO THINK
Novosadov [1.4K]

Answer:

what's the question?..................

3 0
3 years ago
Which equation has exactly two real and two non real solutions?
tatiyna

Answer:

The first option x^4-21x^2-100=0.

Step-by-step explanation:

To have exactly 2 real and two non real solutions, the degree of the polynomial must be a degree 4. Degree is the highest exponent value in the polynomial and is also the number of solutions to the polynomial. This polynomial ha 2 real+2 non real= 4 solutions and must be x^4. This eliminates the bottom two solutions.

In order to have two real and two non real solutions, the polynomial must factor. If it factors all the way like

x^4-100x^2=0\\x^2(x^2-100)=0\\x^2(x-10)(x+10)=0\\\\x^2=0\\x-10=0\\x+10=0

This means x=0, 10, -10 are real solutions to the polynomial. It has no non real solutions. This eliminates this answer choice.

Only answer choice 1 meets the requirement.

5 0
3 years ago
Read 2 more answers
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