Y = mx + b
m = (8 - 0)/(0 - -2) = 8/2 = 4
y = 4x + b
substitute in set of coordinates:
0 = 4(-2) + b
0 = -8 + b
b = 8
y = 4x + 8
8.83176088663 is the answer
Complete question is;
The terminal side of angle θ in standard position, intersects the unit circle at P(-10/26, -24/26). What is the value of csc θ?
Answer:
csc θ = -13/12
Step-by-step explanation:
We know that in a unit circle;
(x, y) = (cos θ, sin θ)
Since the the terminal sides intersects P at the coordinates P(-10/26, -24/26), we can say that;
cos θ = -10/26
sin θ = -24/26
Now we want to find csc θ.
From trigonometric ratios, csc θ = 1/sin θ
Thus;
csc θ = 1/(-24/26)
csc θ = -26/24
csc θ = -13/12
Answer:
What is (f–g)(x)?
f(x)=
–
2x2+10x
g(x)=11
–
3x2
12
Step-by-step explanation:
Answer:
N=R/P−C/P
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable
